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balu736 [363]
3 years ago
13

Determine the equation of a circle with its centre at the origin in the Cartesian plane and with a radius of 2√3 units​

Mathematics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

x^2 + y^2 = 12

Step-by-step explanation:

For a circle with the center at the origin [(h,k) is (0,0)]

use the formula:

x^2 + y^2 = r^2

In this case r is 2sqroot3.

(2sqroot3)^2 is 12.

2•2•sqrt3•sqrt3

= 4•3

= 12

So we get,

x^2 + y^2 = 12

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guajiro [1.7K]

Answer:

  (a)  3 ft, 4 ft, 5 ft

Step-by-step explanation:

The triangle inequality requires the sum of the two short sides exceed the long side.

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a) 3 ft + 4 ft = 7 ft > 5 ft . . . . . triangle is possible

b) 4 yd + 1 2/3 yd = 5 2/3 yd < 10 yd . . . . not a possible triangle

c) 3 ft + 3 ft = 6 ft < 7 ft . . . . not a possible triangle

d) 4 in + 4 in = 8 in . . . . not a possible triangle (not greater than 8 in)

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Step-by-step explanation:

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3 years ago
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natta225 [31]

Answer:

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3 years ago
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Rashid [163]
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Answer:

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