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balu736 [363]
2 years ago
13

Determine the equation of a circle with its centre at the origin in the Cartesian plane and with a radius of 2√3 units​

Mathematics
1 answer:
mojhsa [17]2 years ago
7 0

Answer:

x^2 + y^2 = 12

Step-by-step explanation:

For a circle with the center at the origin [(h,k) is (0,0)]

use the formula:

x^2 + y^2 = r^2

In this case r is 2sqroot3.

(2sqroot3)^2 is 12.

2•2•sqrt3•sqrt3

= 4•3

= 12

So we get,

x^2 + y^2 = 12

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H(t) = −t2 + t + 1 h(−1)
Gwar [14]

Based on the given parameters, the value of the function h(-1) is -1

<h3>How to evaluate the function?</h3>

The equation of the function is given as:

h(t) =-t^2 + t + 1

The function is given as:

h(-1)

This means that t = -1

So, we substitute t = -1 in the equation h(t) =-t^2 + t + 1

h(-1) =-(-1)^2 + (-1) + 1

Evaluate the exponent

h(-1) =-1 - 1 + 1

Evaluate the like terms

h(-1) = -1

Hence, the value of the function h(-1) is -1

Read more about functions at:

brainly.com/question/1415456

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<u>Complete question</u>

Consider the following function definition, and calculate the value of the function

h(t) = −t2 + t + 1 h(−1)

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2 years ago
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tangare [24]
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4 0
2 years ago
3.<br> -4r – 6 + 6r + 9 = 29
SIZIF [17.4K]

Answer:

r=13

Step-by-step explanation:

8 0
3 years ago
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Find the sum of 362+265.explain why you did or did not regroup.
Vesna [10]
EDIT:
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3 years ago
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Find the sum of a finite geometric sequence from n = 1 to n = 8, using the expression −2(3)^n − 1.
Kazeer [188]
The sum if the geometric sequence given by:
an=-2(3)^(n-1)
will be:
when:
n=1
an=-2
when n=2
a2=-6
when n=3
a3=-18

when n=4
a4=-54

when n=5
a5=-162

when n=6
a6=-486

when n=7
a7=-1458

when n=8
a8=-4374

thus the summation of the term will be:
Sn=(-4374+-1458+-486+-162+-54+-18+-6+-2)
Sn=-6560
the answer is -6560

6 0
3 years ago
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