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balu736 [363]
3 years ago
13

Determine the equation of a circle with its centre at the origin in the Cartesian plane and with a radius of 2√3 units​

Mathematics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

x^2 + y^2 = 12

Step-by-step explanation:

For a circle with the center at the origin [(h,k) is (0,0)]

use the formula:

x^2 + y^2 = r^2

In this case r is 2sqroot3.

(2sqroot3)^2 is 12.

2•2•sqrt3•sqrt3

= 4•3

= 12

So we get,

x^2 + y^2 = 12

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The solution to the linear expressions are:

  • a. $36.26
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<h3>Solving linear expressions:</h3>

The solution to linear expression is determined by taking into consideration the arithmetic operations used in each linear expression.

From the information given:

a. $18.79 + $2.11 + ‐$1.92 + $17.28

By rearrangement:

= $18.79 + $2.11 + $17.28 ‐$1.92

= $36.26

b. $7.45 + ‐$24.45 + $74.17 + ‐$76.52

By rearrangement:

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= -$19.35

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By rearrangement:

= $98.45 + $2.82 − $10.63 − $20.26

= $70.38

Learn more about solving linear expressions here:

brainly.com/question/2030026

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2 years ago
What is the energy of an object has due to it’s motion is called wat
Snowcat [4.5K]

Answer:

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Step-by-step explanation:

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Then as soon body starts moving with a certain speed "v" there is conservation of energy from Potential energy to Kinetic energy given as product of a half with mass of the body and square of its velocity.

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Answer:

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Step-by-step explanation:

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