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IRISSAK [1]
2 years ago
14

Find the formula for the nth term of the arithmetic sequence -39, 61, 161, 261, ...

Mathematics
1 answer:
maksim [4K]2 years ago
6 0
<h3>Given that it is arithmetic</h3>

d = a_{2} - a_{1} = 61 - ( - 39) = 100

a_{n} = a_{1} + (n - 1)d \\ a_{n} = - 39+ 100 (n - 1) \\ a_{n} =  - 39 + 100n - 100 \\ a_{n} =  - 139 + 100n

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Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)
JulijaS [17]

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

<u>Step-by-step explanation:</u>

We need to find sum of sequence  : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

a=46\\d=42-46=-4

So , Let's calculate how many terms are there as :

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⇒ -496=(n-1)(-4)

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Sum of an AP is :

⇒ S_n = \frac{n}{2}(2a+(n-1)d)

⇒ S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))

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⇒ S_1_2_5 =-25,250

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

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3 years ago
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I’m confused. lol. Pls help
AlexFokin [52]

Answer:

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(-3,1)

3 0
3 years ago
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