Two lines are perpendicular between each other if their slopes fulfills the following property
where m1 and m2 represents the slopes of line 1 an 2, respectively.
To find the slope of a line we can write it in the form slope-intercept form
Our original line is
Then its slope is
Now we have to find the slope of the second line. Using the first property,
Then the second line has to have a slope of 8.
The options given to us are:
Then we have to determine which of these options have a slope of 8. To do that we write them in the slope-intercept form:
Once we have the options in the right form, we note that the only one of them that has a slope of 8 is the last one.
Then the line perpendicular to the original one is
Recall that the characteristic polynomial of a 2x2 matrix
is
but
and
, so the characteristic polynomial for
is
We're given that the trace is 15 and determinant is 50, so the characteristic polynomial for the matrix in question is
and the eigenvalues are those
for which the characteristic polynomial evaluates to 0.
Answer:
x= 3sqrt2 y=3
Step-by-step explanation:
The triangle is isosceles triangle, which means 2 sides are congruent. Therefore, y =3
using the pythagorean theorem,
3^2+3^2=x^2
9+9=x^2
18=x^2
x=18 sqrt
3sqrt2
Number one=d
number two=b
number three=a
X= -1, -5/2
Hope this helps