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Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions

Pachacha [2.7K]

Answer:

$132\ in^{2}$ is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the box

we have

$L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in$

$W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in$

$H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in$

Find the area of the base B

$B=LW$

$B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}$

Find the perimeter of the base P

$P=2(L+W)$

$P=2(\frac{31}{4}+\frac{13}{4}))$

$P=2(\frac{44}{4})=22\ in$

Find the surface area

$SA=2(\frac{403}{16})+22(\frac{31}{8})$

$SA=(\frac{403}{8})+(\frac{682}{8})$

$SA=\frac{1,085}{8}=135.625\ in^{2}$

6 0

3 years ago

emily just hired a new employee to work in your bakeshop . in one hour the empolyee burned 750 choclat chip cookies . if this re

Ivan

You planned on making 5000 cookies

4 0

3 years ago

Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC

e-lub [12.9K]

Answer:

$DC=\frac{8}{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

In the right triangle ABM

Applying the Pythagorean Theorem

$BM^2=AB^2-AM^2$

we have

$AB=5\ units\\AM=x\ units$

substitute

$BM^2=5^2-x^2$

$BM^2=25-x^2$ -----> equation A

In the right triangle BMC

Applying the Pythagorean Theorem

$BM^2=BC^2-MC^2$

we have

$BC=7\ units\\MC=AC-AM=(9-x)\ units$

substitute

$BM^2=7^2-(9-x)^2$

$BM^2=49-(81-18x+x^2)$

$BM^2=49-81+18x-x^2$

$BM^2=-x^2+18x-32$ ----> equation B

equate equation A and equation B

$-x^2+18x-32=25-x^2$

solve for x

$18x=25+32\\18x=57\\\\x=\frac{57}{18}$

Simplify

$x=\frac{19}{6}$

Find the length of DC

$DC=AC-2x$

substitute the given values

$DC=9-2(\frac{19}{6})$

$DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units$

8 0

3 years ago

Reuben bought a desktop computer and a laptop computer. Before finance charges, the laptop cost $150 more than the desktop. He p

cupoosta [38]

Same case as Pablo's, more or less.

a = price for the desktop

b = price for the laptop

we know the laptop is 150 bucks more than the desktop, b = a + 150.

how much is 7% of a? (7/100) * a, 0.07a.

how much is 9.5% of b? (9.5/100) * b, 0.095b.

total interests for the financing add up to 303, 0.07a + 0.095b = 303.

$\bf \begin{cases}
\boxed{b}=a+150\\
0.07a+0.095b=303\\
----------\\
0.07a+0.095\left(\boxed{a+150} \right)=303
\end{cases}
\\\\\\
0.07a+0.095a+14.25=303\implies 0.165a=288.75
\\\\\\
a=\cfrac{288.75}{0.165}\implies a=1750$

how much was it for the laptop? well b = a + 150.

8 0

3 years ago

PLEASE HELP ASAP! need answer now!

BARSIC [14]

Answer:

i have the same question

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers