Oh. I thought you meant 3-6, not questions 3 through 6. Sorry :(
I assume you mean one that is not rational, such as √2. In such a case, you make a reasonable estimate of it's position, and then label the point that you plot.
For example, you know that √2 is greater than 1 and less than 2, so put the point at about 1½ (actual value is about 1.4142).
For √3, you know the answer is still less than 4, but greater than √2. If both of those points are required to be plotted just make sure you put it in proper relation, otherwise about 1¾ is plenty good (actual value is about 1.7321).
If you are going to get into larger numbers, it's not a bad idea to just learn a few roots. Certainly 2, 3, and 5 (2.2361) and 10 (3.1623) shouldn't be too hard.
Then for a number like 20, which you can quickly workout is √4•√5 or 2√5, you could easily guess about 4½ (4.4721).
They're usually not really interested in your graphing skills on this sort of exercise. They just want you to demonstrate that you have a grasp of the magnitude of irrational numbers.
Answer:
The length of the unknown side x is 4 cm
Step-by-step explanation:
we know that
The perimeter of a polygon is equal to the sum of its length sides
Remember that
1 cm=10 mm
In this problem we have
AB=45 mm ------> convert to cm -----> AB=45/10=4.5 cm
BC=10 cm 4 mm -----> convert to cm -----> BC=10+4/10=10.4 cm
CD=5 cm 6 mm -----> convert to cm -----> CD=5+6/10=5.6 cm
DE=35 mm ------> convert to cm -----> DE=35/10=3.5 cm
EA=x cm
P=280 mm ------> convert to cm -----> P=280/10=28 cm
The perimeter of the irregular polygon is equal to
P=AB+BC+CD+DE+EA
substitute the values
28=4.5+10.4+5.6+3.5+x
28=24+x
x=28-24
x=4 cm
Answer:
x is equal to -21
Step-by-step explanation:
-21+4=-17
0 is the only degree that cannot work
