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2 years ago

Find the area and the circumference of a circle with cameter 5 yd.

Mathematics

1 answer:

mixas84 [53]2 years ago

4 0

Answer:

2πr²

2π•2.5²

2π•6.25

2•3.14•6.25

39.25

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What is the value of x? O 13 O 14 O 26 O 28

BartSMP [9]

It’s A. 13

hope this helps

7 0

2 years ago

Johnny spend 1/7 of his income on Food, 1/10 of his income on gas, and 3/8 of his income on rent. What percentage of his income

Agata [3.3K]

Answer:

38.2%

Step-by-step explanation:

1/7 ≈ 14.29%

1/10 = 10.00%

3/8 = 37.50%

The total that Johnny has allocated for food, gas, and rent is ...

14.29% + 10.00% + 37.50% = 61.79%

So, the remaining amount is ...

100% -61.79% = 38.21%

About 38.2% of Johnny's income remains.

7 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago

Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the d

lesya [120]

Answer:

segment EH and segment E prime H prime both pass through the center of dilation.

Step-by-step explanation:

Center of dilation is point (0.1), same as H. Both, E(0,5) and H(0,1) are placed over y-axis, then E' and H' are also located at y-axis.

After dilation, H' is placed at (0,1) because it coincides with the center of dilation

Distance between E and center of dilation is 4 units, then E' should be at 4*3=12 units from the center of dilation and over y-axis. Therefore, E' is placed at (0, 13)

So, segment E'H' goes from (0,1) to (0,13), and pass through the center of dilation, like segment EH.

4 0

3 years ago

Which description best defines FG¯¯¯¯¯ ?

kogti [31]

The answer is A because say there is point H between F and G the point would be considered summarised by F and G

8 0

3 years ago

Read 2 more answers