A to the 6th divided by a to the 2nd
You get 20$ dollars. Because if you divide 35 by 7 you get 5 then times 5*4=20
lx-1 l ≤ 13
There are 2 solutions:
x-1 ≤ 13
and
x-1 ≥ -13
Solve each one
x-1 ≤ 13
add 1 to both sides of the equation
x-1+1≤ 13+1
x ≤ 14
x-1 ≥ -13
Add 1 to both sides:
x-1+1 ≥-13+1
x ≥ -12
-12 ≤ x ≤ 14
Answer:
1953/6724
Step-by-step explanation:
The first person is choosing a student that is male
There are 84 males out of the 164 students
P(male) = male/total = 84/164 =21/41
The second person is choosing a student that is going to community college
There are 93 males out of the 164 students
P(college) = college/total = 93/164
Multiply the two probabilities together
P(male then college) = 21/41 * 93/164 = 1953/6724
Answer:
The correct option is;
CGB
Whereby, we have;
Triangle RKB ~ Triangle CGB
Step-by-step explanation:
The given triangles have the following congruent angles;
Angle ∠RKB on triangle ΔRKB is congruent to angle ∠CGB on triangle ΔCGB
We are given angle ∠KBR on triangle ΔRKB is congruent to angle ∠GBC on triangle ΔCGB
Therefore, ΔRKB is similar to ΔCGB by the Angle-Angle (AA) rule for similarity.