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2 years ago

What is the slope from the coordinate points (2,6) (1,9)

Mathematics

2 answers:

Hunter-Best [27]2 years ago

8 0

Answer:

$m=-3$

General Formulas and Concepts:

Pre-Alg

Order of Operations: BPEMDAS

Alg I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (2, 6)

Point (1, 9)

Step 2: Find slope m

Substitute: $m=\frac{9-6}{1-2}$
Subtract: $m=\frac{3}{-1}$
Divide: $m=-3$

lesya [120]2 years ago

4 0

Answer:

-3

Step-by-step explanation:

The equation for the slope is the change in y/ the change x.

In order to find the change in y we have to subtract the second y (9) by the first y(6) and do the same for x.

That will be (9 - 6)/(1 - 2) = 3/-1 = -3

Slope is -3

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Answer:

$3.90

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3 years ago

Find the price of a $50 item after a 20% discount

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The average heights of x number of girls and 15 boys is 123. if the average heights of boys is 125 and that of girls is 120.find

mamaluj [8]

Answer:

$x = 10$ . In other words, there number of girls is $10$ .

Step-by-step explanation:

The average of a number of measurements is equal to the sum of these measurements over the number of measurements.

$\displaystyle \text{Average} = \frac{\text{Sum of measurements}}{\text{Number of measurements}}$ .

Rewrite to obtain:

$\begin{aligned}& \text{Sum of measurements}= (\text{Number of measurements}) \times (\text{Average}) \end{aligned}$ .

For this question:

$\begin{aligned}& \text{Sum of heights of boys} \\ &= (\text{Number of boys}) \times (\text{Average height of boys}) \\ &= 15 \times 125 = 1875\end{aligned}$ .

$\begin{aligned}& \text{Sum of heights of girls} \\ &= (\text{Number of girls}) \times (\text{Average height of girls}) \\ &= x \times 120 = 120\, x\end{aligned}$ .

Therefore:

$\begin{aligned}& \text{Sum of boys and girls} \\ &= \text{Sum of heights of boys} + \text{Sum of heights of girls}\\ &= 1875 + 120\, x\end{aligned}$ .

On the other hand, there are $(15 + x)$ boys and girls in total. Using the formula for average:

$\begin{aligned}& \text{Average height of boys and girls} \\ &= \frac{\text{Sum of heights of boys and girls}}{\text{Number of boys and girls}} \\ &= \frac{1875 + 120\, x}{15 + x}\end{aligned}$ .

From the question, this average should be equal to $123$ . In other words:

$\displaystyle \frac{1875 + 120\, x}{15 + x} = 123$ .

Solve this equation for $x$ to obtain:

$1875 + 120\, x= 123\, (15 + x)$ .

$(123 - 120)\, x = 1875 - 123 \times 15$ .

$x = 10$ .

In other words, the number of girls here is $10$ .

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2 years ago

Jean and Jericho who are playing in the school grounds decided to sit on a

Natalija [7]

We want to see underline the correct part in each statement.

1) This situation illustrates (direct, inverse) variation.
2) The two quantities that must vary in this situation are (weight and 
distance from the center, height and weight).
3) The heavier the kid, the (closer, farther) he/she should be at the
center to balance the seesaw?
4) When Jean moves farther from the center, Jericho tends to go (up,
down).
5) If Jericho moves closer to the center, Jean tends to go (up, down).

So, Jean and Jericho are playing on a seesaw.

Jean is heavier than Jericho.

Now, notice that a seesaw is a lever. So it "amplificates" the force that you apply in one end to lift the weight that is on the other end. Depending on the form of the lever and the weights, the force that you need to do changes.

If we define:

W₁ = Jean's weight.
d₁ = Jean's distance to the center.
W₂ = Jericho's weight.
d₂ = Jericho's distance to the center.

We must have:

W₁*d₁ = W₂*d₂

Then:

1) This situation illustrates (direct, inverse) variation.

d₁, the position of Jean, varies inversely with respect to Jean's weight.

2) The two quantities that must vary in this situation are (weight and

distance from the center, height and weight).

(by the equation above)

3) The heavier the kid, the (closer, farther) he/she should be at the

center to balance the seesaw?

By the given equation, we see that d₁ must be smaller than d₂.

And the last two are trivial:

4) When Jean moves farther from the center, Jericho tends to go (up,

down).

5) If Jericho moves closer to the center, Jean tends to go (up, down).

If you want to learn more, you can read:

brainly.com/question/18320907

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