All categories

3 years ago

This recipe makes 5 portions of potato soup.

Mathematics

1 answer:

Sindrei [870]3 years ago

6 0

Answer:

90 mL oil

210 g onions

1,350 g potatoes

1,500 mL milk

Step-by-step explanation:

You would just multiply each thing by 3, because the original recipe is for 5 but he wants to make it for 15, which is 3 times the original

You might be interested in

Please help me. this is hard

allochka39001 [22]

Since it is a square that means each side is equal.
The perimeter is 24, and since there is four sides we would divide it by four to find the length of each side.

24/4 = 6

Each side is 6.
By looking at the picture, one side of the square, is the length of the radius.

The radius of the square is 6.

The only thing left to do is to find the circumference.
The circumference formulas are:

C = $\pi$ d
C = 2 $\pi$ r

We can use the first one Diameter x pi (3.14)
To find the diameter we would just multiply the radius by two.

6 x 2 = 12

Diameter = 12

So multiply it by pi

12 x 3.14 = 37.68
or D 12 $\pi$

7 0

3 years ago

Find the coefficient of the x7y2term in the binomial expansion of (x+y)^9

statuscvo [17]

Answer:

Step-by-step explanation:

first, see the formula in the attached picture.

now, by applying that formula we get :

the coefficient of the x7y2 is :

9C7 = 36 (you can either use a calculator or just the algebraic formula)

8 0

3 years ago

F. one die is rolled 3 times. what is the chance of getting no 2's?

aniked [119]

6^3 = 216. When using chance, take the number of outcomes(six for a die) and raise it to the power of the number of repetitions

6 0

3 years ago

Help!!! This question is confusing me!!

erica [24]

Answer:

k ≥2

Step-by-step explanation:

k+ 1/3≥7/3

Subtract 1/3 from each side

k+ 1/3-1/3≥7/3-1/3

k ≥6/3

k ≥2

8 0

3 years ago

Computer keyboard failures are due to faulty electrical connects (12%) or mechanical defects (88%). Mechanical defects are relat

anzhelika [568]

Answer:

(c) Probability that a failure is due to loose keys = 0.2376

(d) Probability that a failure is due to improperly connected or poorly welded wires = 0.078

Step-by-step explanation:

The Whole probability scenario is given for Computer Keyboard failures.

(a) Let F be the event of failure due to faulty electrical connects, P(F) = 0.12

M be the event of failure due to mechanical defects, P(M) = 0.88

LK be the event of mechanical defect due to loose keys, P(LK/M) = 0.27

IA be the event of mechanical defect due to improper assembly, P(IA/M) =0.73

DW be the event of electrical connects due to defective wires,P(DW/F) = 0.35

IC be the event of electrical connects due to improper connections,

P(IC/F) = 0.13 .

PWW be the event of electrical connects due to poorly welded wires,

P(PWW/F) = 0.52

(b) Keyboard failures

Faulty electrical connects Mechanical Defects

P(F) = 0.12 P(M) = 0.88

Defective wires Improper Poorly Loose Keys Improper

P(DW/F)=0.35 Connections Welded wires P(LK/M)=0.27 Assembly

P(IC/F)=0.13 P(PWW/F)=0.52 P(IA/M)=0.73

This is the required tree diagram.

P(LK) =P(LK/M) * P(M) {This means mechanical failure is due to loose

keys}

P(LK) = 0.27 * 0.88 = 0.2376 .

(d) Probability that a failure is due to improperly connected or poorly welded

wires is given by P(IC $\bigcup$ PWW) ;

P(IC $\bigcup$ PWW) = P(IC) + P(PWW) - P(IC $\bigcap$ PWW) { Here P(IC $\bigcap$ PWW) = 0 }

P(IC) = P(IC/F) * P(F) = 0.13 * 0.12 = 0.0156

P(PWW) = P(PWW/F) * P(F) = 0.52 * 0.13 = 0.0676

Therefore, P(IC $\bigcup$ PWW) = 0.0156 + 0.0676 - 0 = 0.078 .

8 0

3 years ago