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lozanna [386]
3 years ago
12

The image below shows two parallel lines cut by a transversal. What is the value of A

Mathematics
1 answer:
rewona [7]3 years ago
3 0

<u>Answer</u>

59°


<u>Explanation</u>

There are 2 parallel line and one transverse.

Angles in a straight line add up to 180°

∴ 180 - (2a + 3) = 180 - 2a -3

                        = 177 - 2a

The angle (177 - 2a) corresponds to angle a in the diagram. The two corresponding angles are equal.

∴ 177 - 2a = a

  177 = a + 2a

3a  = 177

a = 177/3

  = 59°

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6x^2 should be one of them if i am not mistaken!
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3 years ago
Hi ..<br>I really need help on this one <br>​
IgorLugansk [536]

Answer:

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Step-by-step explanation:

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3 years ago
A desest tortoise spends about 95% of its life in underground burrows.About what fraction of a desert tortoise's life is spent a
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5/100's tortoise's life was spent above ground.
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4 years ago
The sum of the measures of two complementary angles exceeds the difference of their measure by 86_. Find the measure of each ang
Bad White [126]

As the sum of two complementary angles = a + b = 90 degree -------(1)

Difference of two complementary angles = a – b

According to question;

The difference of two complementary angles exceed the sume (90) by 86.

So

a – b = 90 – 86 = 4 -------(2)

adding equation (1) and (2);

2a = 90 + 4 = 94

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4 years ago
In the spring of 2017, the Consumer Reports National Research Center conducted a survey of 1,007 adults to learn about their maj
musickatia [10]

Answer:

a) 0.567

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c) (0.5364,0.5976)                  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1007

Number of respondent that  they will be able to afford health insurance in the future, x = 571

a)  point estimate of the population proportion

\hat{p} = \displaystyle\frac{x}{n} = \frac{571}{1007} = 0.567

b) 90% Confidence Interval.

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0.567 \pm 1.64\times \sqrt{\dfrac{0.567(1-0.567)}{1007}}\\\\0.567 \pm 0.0256=(0.5414,0.5926)

c) 95% Confidence Interval.

\hat{p} + z_{\text{critical}}\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting values, we get,

0.567 \pm 1.96\times \sqrt{\dfrac{0.567(1-0.567)}{1007}}\\\\0.567 \pm 0.0306=(0.5364,0.5976)

5 0
4 years ago
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