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Rudiy27
3 years ago
10

F. one die is rolled 3 times. what is the chance of getting no 2's?

Mathematics
1 answer:
aniked [119]3 years ago
6 0
6^3 = 216. When using chance, take the number of outcomes(six for a die) and raise it to the power of the number of repetitions 
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Answer:

g(x)=4(3)^{x+1}+8

Step-by-step explanation:

Given:

The original function is given as:

f(x)=2(3)^{x+1}+4

The above function is stretched vertically by a factor of 2 to form the graph of g(x).

According to the rule of function transformations, when the graph of a function is stretched in the vertical direction by a factor of 'C', where, 'C' is a number greater than 1, then the function rule is given as:

f(x)\to Cf(x)

Therefore, the function is multiplied by a factor of 'C' to get the equation of the stretched function.

Here, the the value of 'C' is 2. So, the equation of g(x) is given as:

g(x)=2f(x)\\g(x)=2[2(3)^{x+1}+4]\\g(x)=4(3)^{x+1}+8

Therefore, the equation of g(x) is g(x)=4(3)^{x+1}+8.

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3 years ago
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Svetllana [295]

Answer:

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Step-by-step explanation:

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There are too many solutions to these equations. 


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