Answer:
Probability of sum of pips on two faces is at least 9 = 
Step-by-step explanation:
Experiment: Throwing two fair dice.
Total no of Outcome = 
= 36
Sample space (list of outcome) is attached.
Let E be the event that sum of pips on two faces is at least 9.
Favorable outcome are where sum is 9 , 10 , 11 and 12.
From Sample space, No. of Favorable outcome = 10
∴ 
She has 52 card all together so she has a probability of drawing on the first draw 4 L's or R's because their are two sets of alphabet cards. So that is 4/52 or 1/13 to the lowest term. Second turn she only has 51 cards to draw from and still has 4 L's and R's so that would be 4/51 and on the third try she has only 50 cards left so that would be 4/50 or 2/25 to the lowest term. Now multiply all three factions 1/13 x 4/51 x 2/25 = 8/16575 meaning out of the three draws she has a probability of getting a L or R, 8 out of 16575 each draw.
Answer:
32
Step-by-step explanation:
it is true; just work them out, you should get what they got :))
