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4 years ago

Find the midpoint of the line segment joining points A(6,-5) and B(,6,1)

Mathematics

2 answers:

rjkz [21]4 years ago

5 0

<h3>Answer: (6, -2)</h3>

Explanation:

The two given points have x coordinates of x = 6 each. They add to 6+6 = 12. Divide this in half to get 12/2 = 6. Since the x coordinates were both the same, the midpoint x coordinate is the same as well.

The y coordinates are a bit more interesting. Add them up to get -5+1 = -4. Then cut this in half to get -4/2 = -2. The y coordinate of the midpoint is -2.

Overall, the midpoint is (6, -2)

s344n2d4d5 [400]4 years ago

4 0

Answer:

the answer is (6.-2)...

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For f(x)=2x+1 and g(x)=x^2-7, find (f+g)(x) A. 2x^2-15 B.X^2+2x-6 C.2x^3-6 D.x^2+2x+8

Advocard [28]

Answer:

Step-by-step explanation:

(f + g)(x) = f(x) + g(x) , thus

f(x) + g(x)

= 2x + 1 + x² - 7 ← collect like terms

= x² + 2x - 6 → C

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Answer:

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3 years ago

Item 7

Mariulka [41]

Answer:

$A = 74.7^\circ$

$B = 42.5^\circ$

$C = 62.8^\circ$

Step-by-step explanation:

Given

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$d = \sqrt{(-1 - 2)^2 + (2 - 8)^2$

$d = \sqrt{(-3)^2 + (-6)^2$

$d = \sqrt{45$

So:

$AB = \sqrt{45$

For BC

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

$BC = \sqrt{(2 - 4)^2 + (8 - 1)^2$

$BC = \sqrt{(-2)^2 + (7)^2$

$BC = \sqrt{53$

For AC

$A = (-1,2) \to (x_1,y_1)$

$C = (4,1) \to (x_3,y_3)$

$AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2$

$AC = \sqrt{(-5)^2 + (1)^2$

$AC = \sqrt{26$

So, we have:

$AB = \sqrt{45$

$BC = \sqrt{53$

$AC = \sqrt{26$

By representation

$AB \to c$

$BC \to a$

$AC \to b$

So, we have:

$a = \sqrt{53$

$b = \sqrt{26$

$c = \sqrt{45$

By cosine laws, the angles are calculated using:

$a^2 = b^2 + c^2 -2bc \cos A$

$b^2 = a^2 + c^2 -2ac \cos B$

$c^2 = a^2 + b^2 -2ab\ cos C$

$a^2 = b^2 + c^2 -2bc \cos A$

$(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A$

$53 = 26 +45 - 2 * 34.21 * \cos A$

$53 = 26 +45 - 68.42 * \cos A$

Collect like terms

$53 - 26 -45 = - 68.42 * \cos A$

$-18 = - 68.42 * \cos A$

Solve for $\cos A$

$\cos A =\frac{-18}{-68.42}$

$\cos A =0.2631$

Take arc cos of both sides

$A =\cos^{-1}(0.2631)$

$A = 74.7^\circ$

$b^2 = a^2 + c^2 -2ac \cos B$

$(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B$

$26 = 53 +45 -97.67 * \cos B$

Collect like terms

$26 - 53 -45= -97.67 * \cos B$

$-72= -97.67 * \cos B$

Solve for $\cos B$

$\cos B = \frac{-72}{-97.67}$

$\cos B = 0.7372$

Take arc cos of both sides

$B = \cos^{-1}(0.7372)$

$B = 42.5^\circ$

For the third angle, we use:

$A + B + C = 180$ --- angles in a triangle

Make C the subject

$C = 180 - A -B$

$C = 180 - 74.7 -42.5$

$C = 62.8^\circ$

8 0

3 years ago

What is the exact area and circumference?

Rudik [331]

Answer:

Step-by-step explanation:

The area of a circle is calculated using the formula: πr^2

The circumference of a circle is calculated using: 2πr

We are given 8 questions, So by addressing them individually

1) Area of Circle 1:

Radius = r = 12 mi

Total angle in a circle = 360°

Given angle = 90

Ratio of given circle to complete circle = 90/360

=> 1/4

Therefore, the circle 1 is 1/4 of the complete circle with r = 12.

In this way, its area will be 1/4 of the complete circle.

Hence

Area = 1/4 (πr^2)

=> 1/4 (π*12^2 )

=> 1/4 (144π)

=> 36π Hence option C

2) Area of Circle 2:

Radius = r = 19 in

Total angle in a circle = 360°

Given angle = 315

Ratio of given circle to complete circle = 315/360

=> 7/8

Therefore, the circle 2 is 7/8 of the complete circle with r = 19.

In this way, its area will be 7/8 of the complete circle.

Hence

Area = 7/8 (πr^2)

=> 7/8 (π*19^2 )

=> 7/8 (361π)

=> 315.8π Hence answer is not provided that is option f

3) Area of Circle 3:

Radius = r = 15 km

Total angle in a circle = 360°

Given angle = 270

Ratio of given circle to complete circle = 270/360

=> 3/4

Therefore, the circle 3 is 3/4 of the complete circle with r = 15.

In this way, its area will be 3/4 of the complete circle.

Hence

Area = 3/4 (πr^2)

=> 3/4 (π*15^2 )

=> 3/4 (225π)

=> 168.75π Hence answer is not provided that is option f

4) Area of Circle 4:

Radius = r = 6 km

Total angle in a circle = 360°

Given angle = 270

Ratio of given circle to complete circle = 90/360

=> 3/4

Therefore, the circle 4 is 3/4 of the complete circle with r = 6.

In this way, its area will be 3/4 of the complete circle.

Hence

Area = 3/4 (πr^2)

=> 3/4 (π*6^2 )

=> 3/4 (36π)

=> 27π Hence answer is not provided that is option f

5) Circumference of Circle 1:

Radius = r = 12 mi

Total angle in a circle = 360°

Given angle = 90

Ratio of given circle to complete circle = 90/360

=> 1/4

Therefore, the circle 1 is 1/4 of the complete circle with r = 12.

In this way, its circumference will be 1/4 of the complete circle. In addition to that, its boundary will include the radius of both sides to make it a close shape.

Hence

Circumference = 1/4 (2πr) + 2r

=> 1/4 (2π12) + 2*12

=> 1/4 (24π) + 24

=> 6π + 24 Hence answer is not provided that is option f

6) Circumference of Circle 2:

Radius = r = 19 in

Total angle in a circle = 360°

Given angle = 315

Ratio of given circle to complete circle = 315/360

=> 7/8

Therefore, the circle 2 is 7/8 of the complete circle with r = 19.

In this way, its circumference will be 7/8 of the complete circle. In addition to that, its boundary will include the radius of both sides to make it a close shape.

Hence

Circumference = 7/8 (2πr) + 2r

=> 7/8 (2π19) + 2*19

=> 7/8 (38π) + 38

=> 33.25π + 38 Hence answer is not provided that is option f

7) Circumference of Circle 3:

Radius = r = 15 km

Total angle in a circle = 360°

Given angle = 270

Ratio of given circle to complete circle = 270/360

=> 3/4

Therefore, the circle 3 is 3/4 of the complete circle with r = 15.

In this way, its circumference will be 3/4 of the complete circle. In addition to that, its boundary will include the radius of both sides to make it a close shape.

Hence

Circumference = 3/4 (2πr) + 2r

=> 3/4 (2π19) + 2*15

=> 3/4 (38π) + 38

=> 28.5π + 38 Hence answer is not provided that is option f

8) Circumference of Circle 4:

Radius = r = 6 km

Total angle in a circle = 360°

Given angle = 270

Ratio of given circle to complete circle = 270/360

=> 3/4

Therefore, the circle 3 is 3/4 of the complete circle with r = 6.

In this way, its circumference will be 3/4 of the complete circle. In addition to that, its boundary will include the radius of both sides to make it a close shape.

Hence

Circumference = 3/4 (2πr) + 2r

=> 3/4 (2π6) + 2*6

=> 3/4 (12π) + 12

=> 9π + 12 Hence answer is not provided that is option f

6 0

3 years ago