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777dan777 [17]
4 years ago
15

A cube-shaped box has a volume of 125 cubic inches. If the box is packed full of cubes with edge lengths of 1 inch, how many cub

es can fit along one face of the box?
Mathematics
1 answer:
harina [27]4 years ago
6 0

I am not sure if I am right, but this is the best I can answer.


Useing reason, and logic, my guess would be if you take 125, and divided it by 4, you would get 31.25. that should be the answer... if i am wrong, i am truely sorry. I havent been in the subject in a while...


                                                           Hope this helps.


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When four gallons are added to a tank that is one-third full, the tank is then one-half full. What is the capacity of the tank i
Dmitry_Shevchenko [17]

The capacity of the tank in gallons is 24 gallons.

<h3>What is an Equation ?</h3>

An equation is a mathematical statement formed when two algebraic expressions are equated by an equal sign.

It is given in the question that

When four gallons are added to a tank that is one-third full

the tank is then one-half full.

Let the capacity of the tank is x gallons

The equation can be formed for the capacity of the tank as

(1/3)x +4 = (1/2)x

(1/3)x -(1/2)x = -4

(1/6)x = 4

x = 24 gallons.

Therefore the capacity of the tank in gallons is 24 gallons.

To know more about Equation

brainly.com/question/2263981

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8 Tatami mats are needed to cover the floor.
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Please Help me on this Question
PSYCHO15rus [73]
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5 0
3 years ago
Select the graph of the solution. click until the correct graph appears. 2x - 1 &gt; 5
Usimov [2.4K]

Answer:

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I have attached a picture of the graph below.

5 0
3 years ago
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
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