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Softa [21]
3 years ago
10

1. Write the ratio of the first measurement to the second: 8 ft. 4 in. to 6 in.

Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0

Answer:

6:100 or 3:50

Step-by-step explanation:

8ft 4 in = 100 inches

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Honda Atlas issued 100,000 shares of stock. In 1990, each share of stock was worth Rs. 152.50. In 1993, each share of the stock
noname [10]

Answer:

Rs.13,130 ,000

Step-by-step explanation:

Lets solve first for year 1990

Value of stock in 1990 = Rs. 152.50

No. of stocks issued in 1990 = 100,000

Total value of these stocks in 1990= Value of stock in 1990* no of stocks issued in 1990  = 152.50*100,000 = Rs. 15,250,000

Let solve first for year 1993

Value of stock in 1993 = Rs. 21.20

No. of stocks   1993 = 100,000

Total value of these stocks in 1993 = Value of stock in 1993* no of stocks issued in 1993  = 21.20*100,000 = Rs. 2,120,000

Decrease in value of stock in 1993 in comparison to 1990 = Total value of the stocks in 1990 -Total value of the stocks in 1993

 =  Rs. 15,250,000 - Rs. 2,120,000

 = Rs.13,130 ,000

Thus, the 100,000 shares worth Rs.13,130 ,000 lesser in 1993 than in 1990.

6 0
3 years ago
a rectangular tabletop has a length of 4 3/4 feet and an area fo 11 7/8 square feet. What is the width of the tabletop?
GenaCL600 [577]
W=A/L; 11 7/8 ÷ 3/34= 3 1/6ft
5 0
3 years ago
Alexander purchased a computer on sale. The original price was $1,200. The sale price was 5/6 of the original price. How much di
gtnhenbr [62]
1160 dollars if you take 5/6 away from 1200 you get 40 subtract 40 from 1200 and you get your answer

6 0
3 years ago
The latest online craze is a new game, Khan on Seven. You get
Alika [10]

Do you have any answer choices?

8 0
4 years ago
Read 2 more answers
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
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