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3 years ago

1. Write the ratio of the first measurement to the second: 8 ft. 4 in. to 6 in.

Mathematics

1 answer:

m_a_m_a [10]3 years ago

3 0

Answer:

6:100 or 3:50

Step-by-step explanation:

8ft 4 in = 100 inches

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What is the median of the data set given below? 26, 39, 18, 21, 24, 48, 21, 35

sergiy2304 [10]

To find the Median, place the numbers you are given in value order and find the middle number. <span>If there are two middle numbers, you average them.
</span><span>18, 21, 21, 24, 26, 35, 39, 48

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If a figure is a square then is it a regular quadrilateral true or false explain

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3 years ago

How do you solve 42 divided by 63

Dafna1 [17]

42 ÷ 63

63 -> 420

63x6=378

420-378=42

63->420

So, how many times does 63 go into 42? Well, it doesn't. So put down a zero on your paper, and then a decimal. So if we add a zero onto 42, it becomes 420. Well, 420 is divisible by 63. In fact, 63 goes into 420 6 times, making a total of 378. 420-378 = 42. Then the process begins again. So you've got a 0.6, and that six just keeps on repeating. On paper, you're gonna wanna put a dash over the six to show that it's repeating.

Anyways, the answer is .66 repeating.

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On a map, 1 inch equals 20 miles. Two cities are 6 inches apart on the map. What is the actual distance between the cities?

Elodia [21]

Answer:

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Step-by-step explanation:

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3 years ago

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Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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3 years ago