Answer:
Total paper required = 165 cm²
Step-by-step explanation:
Paper required to cover the entire block = (Surface area of the prism at the base - area of the top of the prism) + Lateral surface area of the pyramid
Surface area of the rectangular prism = 2(lb + bh + hl)
(here l, b, h are the length, width and height respectively)
= 2(5×5 + 5×4 + 4×5)
= 2(25 + 20 + 20)
= 2×65
= 130 cm²
Area of the top of the prism = (side)²
= 5²
= 25 cm²
Lateral area of the square pyramid = 4 × Area of one lateral side
= 4 × ![[\frac{1}{2}(\text{Base})(\text{Height})]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BBase%7D%29%28%5Ctext%7BHeight%7D%29%5D)
= 4 × ![[\frac{1}{2}(5)(6)]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%285%29%286%29%5D)
= 60 cm²
Total paper required = (130 - 25) + 60
= 105 + 60
= 165 cm²
72000/12=6000 12 pools of equal volume, both start and end are in gallons so it's just basic division.
Answer:
D. Up
Step-by-step explanation:
When a parabola has the form 
, It is vertical (opens up or down).
Because the variable "x" is squared.
If "a" is positive, then the parabola opens up, but if it is negative, then the parabola opens down.
In this case you have the quadratic function:
Which can be rewritten as:
Therefore, it is vertical, because it has the form:
You can observe that the value of "a" is:
Then, since "a" is positive, the parabola opens up.
First, lets subtract the goal by 3, because she already did them.
15 - 3
12
Now, lets divide by one because that will leave you with the number of days
12/1
12
So, It will take her 12 days if she keeps up with her goal.
Hope this helps!
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Explanation:
For the purpose of filling in the table, the BINOMPDF function is more appropriate. The table is asking for p(x)--not p(n≤x), which is what the CDF function gives you.
If you want to use the binomcdf function, the lower and upper limits should probably be the same: 0,0 or 1,1 or 2,2 and so on up to 5,5.
The binomcdf function on my TI-84 calculator only has the upper limit, so I would need to subtract the previous value to find the table entry for p(x).
