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Yuliya22 [10]
3 years ago
5

1. -10=xy+z, solve for x please? 2. h-4/j =k, solve for j please?​

Mathematics
2 answers:
ANEK [815]3 years ago
8 0

Answer:

x=\frac{-10-z}{y}

Step-by-step explanation:

1 Subtract z from both sides.

-10-z=xy

2 Divide both sides by y

\frac{-10-z}{y} =x

3 Switch sides.

x=\frac{-10-z}{y}

2nd question

Answer: j=-\frac{4}{k-h}

Step-by-step explanation:

1 Subtract h from both sides

-\frac{4}{j} =k-h

2 Multiply both sides by j.

-4=(k-h)j

3 Divide both sides by k−h.

-\frac{4}{k-h}=j

4 Switch sides.

j=-\frac{4}{k-h}

pychu [463]3 years ago
5 0

Answer:

\huge \boxed{x= \frac{-10-z}{y} } \\\\\\\\ \huge \boxed{j=\frac{4}{h-k} }

\rule[225]{225}{2}

Step-by-step explanation:

Solving for x:

-10=xy+z

Subtracting z from both sides:

-10-z=xy

Divding both sides by y:

\displaystyle \frac{-10-z}{y} =x

Solving for j:

\displaystyle h-\frac{4}{j} =k

Subtracting h from both sides:

\displaystyle - \frac{4}{j} =-h+k

Multiplying both sides by j,

then dividing both sides by (-h + k):

\displaystyle - \frac{4}{-h+k} =j

Simplifying the equation:

\displaystyle \frac{4}{-(-h+k)} =j

\displaystyle \frac{4}{h-k} =j

\rule[225]{225}{2}

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