Question

1. -10=xy+z, solve for x please? 2. h-4/j =k, solve for j please?​

Answer 1

Answer:

$x=\frac{-10-z}{y}$

Step-by-step explanation:

1 Subtract z from both sides.

$-10-z=xy$

2 Divide both sides by y

$\frac{-10-z}{y} =x$

3 Switch sides.

$x=\frac{-10-z}{y}$

2nd question

Answer: $j=-\frac{4}{k-h}$

Step-by-step explanation:

1 Subtract h from both sides

$-\frac{4}{j} =k-h$

2 Multiply both sides by j.

$-4=(k-h)j$

3 Divide both sides by k−h.

$-\frac{4}{k-h}=j$

4 Switch sides.

$j=-\frac{4}{k-h}$

Answer 2

Answer:

$\huge \boxed{x= \frac{-10-z}{y} } \\\\\\\\ \huge \boxed{j=\frac{4}{h-k} }$

$\rule[225]{225}{2}$

Step-by-step explanation:

Solving for x:

$-10=xy+z$

Subtracting z from both sides:

$-10-z=xy$

Divding both sides by y:

$\displaystyle \frac{-10-z}{y} =x$

Solving for j:

$\displaystyle h-\frac{4}{j} =k$

Subtracting h from both sides:

$\displaystyle - \frac{4}{j} =-h+k$

Multiplying both sides by j,

then dividing both sides by (-h + k):

$\displaystyle - \frac{4}{-h+k} =j$

Simplifying the equation:

$\displaystyle \frac{4}{-(-h+k)} =j$

$\displaystyle \frac{4}{h-k} =j$

$\rule[225]{225}{2}$