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Fiesta28 [93]
3 years ago
15

A fair six sided die is rolled once. What is the probability of rolling a 5 or 6?

Mathematics
2 answers:
kipiarov [429]3 years ago
8 0

Answer:

1/3

Step-by-step explanation:

there are two numbers so it will be 2/6

when you simplify you get 1/3

Anika [276]3 years ago
3 0

Answer:

2/6

Step-by-step explanation:

There are 6 sides on the die. This means each side has a 1/6 chance of appearing on top. If you are either going for 5 or 6, you have a 2/6 chance because it can land on either 5 or 6.

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Ashley has two coupons for a phone.
Andreas93 [3]
I think it’s Coupon A because the price should be 42.25 or about 42 dollars

6 0
3 years ago
A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

45.14% probability that the point estimate was within ±15 of the population mean

3 0
3 years ago
Ou're given two side lengths of 3 centimeters and 5 centimeters. Which measurement can you use for the length of the third side
exis [7]

Answer:

10

Step-by-step explanation:

5 0
3 years ago
[BRAINLIEST] a. Nick deposits money in a Certificate of Deposit account (CD). The balance (in dollars) in his account t years af
crimeas [40]

Answer:

(1.06)0 = 1  and positive powers of 1.06 are larger than 1, thus the minimum value N(t) attains, if t≥0, is 400.

From the point of view of the context, a CD account grows in value over time so with a deposit of $400 the value will never drop to $399.

4 0
2 years ago
You measure 47 backpacks' weights, and find they have a mean weight of 79 ounces. Assume the population standard deviation is 13
ki77a [65]

Answer:

3.14

Step-by-step explanation:

Given that:

Mean weight (m) = 79 ounces

Population standard deviation (s) = 13.1

Sample size = 47

Maximal margin of error associated with 90% confidence interval.

The margin of error is given by:

Zcritical * (standard deviation / sqrt(sample size)

Z critical at 90% confidence interval = 1.645

Hence,

Zcritical * (standard deviation / sqrt(sample size)

1.645 * 13.1 / sqrt(47)

1.645 * (13.1 / 6.8556546)

1.645 * 1.9108313

Hence, the margin of error is :

3.1433174885

= 3.14

8 0
3 years ago
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