The distance from the Earth's center to the point outside the Earth is 55800 Km
<h3>How to determine the distance from the surface of the Earth</h3>
- Acceleration due to gravity of Earth = 9.8 m/s²
- Acceleration due to gravity of the poin (g) = 1/60 × 9.8 = 0.163 m/s²
- Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
- Mass of the Earth (M) = 5.97×10²⁴ Kg
- Distance from the surface of the Earth (r) =?
g = GM / r²
Cross multiply
GM = gr²
Divide both sides by g
r² = GM / g
Take the square root of both sides
r = √(GM / g)
r = √[(6.67×10¯¹¹ × 5.97×10²⁴) / 0.163)]
r = 4.94×10⁷ m
Divide by 1000 to express in Km
r = 4.94×10⁷ / 1000
r = 4.94×10⁴ Km
<h3>How to determine the distance from the center of the Earth</h3>
- Distance from the surface of the Earth (r) = 4.94×10⁴ Km
- Radius of the Earth (R) = 6400 Km
- Distance from the centre of the Earth =?
Distance from the centre of the Earth = R + r
Distance from the centre of the Earth = 6400 + 4.94×10⁴
Distance from the centre of the Earth = 55800 Km
Learn more about gravitational force:
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Answer: 1.59 sec
Explanation:
The kinetic energy contained in the rotation of the cylinder is 1/2 m v^2
The kinetic energy of translation is also 1/2 m v^2
so the total energy is m v^2
The force applied is mg sin (theta)
= m x 9.8 x 1/2
= 4.9 m
Now equate
F x d = m v^2
4.9 m x 3.1 = m v^2
v^2 = 4.9 x 3.1
v = sqrt(4.9 x 3.1) = 3.9 m/s
Acceleration.
V^2 = 2 a s
4.9 x 3.1 = 2 x a x 3.1
4.9 = 2 a
a = 2.45 m/s^2
Time
T = v/a
= 3.9/2.45
= 1.59 sec
Answer:
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