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Veronika [31]
3 years ago
6

4.Give at least three examples from everyday life where an inclined plane is used to reduce the effort force needed to accomplis

h a task.
Physics
1 answer:
olga nikolaevna [1]3 years ago
5 0
1. A wheelchair ramp. Instead of using lifting force on the wheelchair, You use push or pull force on it.

2. A slide. Instead of throwing down an item, It uses gravitational potential energy make an object "move" down the slide.

3.A screw. It's reducing the force by twisting the screw out of something instead of pulling it out. (Sorry about my bad grammar).
You might be interested in
Why do we add the masses together after that inelastic collision?
fomenos

Answer:An inelastic collision is one in which the internal kinetic energy changes (it is not conserved). A collision in which the objects stick together is sometimes called perfectly inelastic because it reduces internal kinetic energy more than does any other type of inelastic collision.People sometimes think that objects must stick together in an inelastic collision. However, objects only stick together during a perfectly inelastic collision. Objects may also bounce off each other or explode apart, and the collision is still considered inelastic as long as kinetic energy is not conserved.

hope this helps have a nice day❤️

Explanation:

5 0
3 years ago
A piece of aluminum has a volume of 4.89 x 10-3 m3. The coefficient of volume expansion for aluminum is = 69 x 10-6(C°)-1. The t
Leno4ka [110]

Answer:

11.515 Joule

Explanation:

Volume of aluminium = V = 4.89×10⁻³ m³

Coefficient of volume expansion for aluminum = α = 69×10⁻⁶ /°C

Initial temperature = 19.1°C

Final temperature = 357°C

Pressure of air = 1.01×10⁵ Pa

Change in temperature = ΔT= 357-19.1 = 337.9 °C

Change in volume

ΔV = αVΔT

⇒ΔV = 69×10⁻⁶×4.89×10⁻³×337.9

⇒ΔV = 114010.839×10⁻⁹ m³

Work done

W = PΔV

⇒W = 1.01×10⁵×114010.839×10⁻⁹

⇒W = 11.515 J

∴ Work is done by the expanding aluminum is 11.515 Joule

7 0
3 years ago
A vehicle moves in a straight line with an
nordsb [41]
The solution to your problem is as follows:

<span>5km/h2 x 1 h/60 min x 1 min/60 sec x 1000m/km = 1.39 meters per second change each second.
</span>
Therefore, the speed change each second is <span>1.39 meters per second change each second.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
7 0
4 years ago
A roller coaster with a potential energy of 235,200 J sits at the top of a 30 m high hill. What is the mass of the roller
xxTIMURxx [149]

Answer:

800 kg

Explanation:

I just did it :)

5 0
3 years ago
Read 2 more answers
To stretch a certain nonlinear spring by an amount x requires a force F given by F = 40 x − 6 x 2 , where F is in Newtons and x
strojnjashka [21]

Answer:

64 J

Explanation:

The potential energy change of the spring ∆U = -W where W = work done by force, F.

Now W = ∫F.dx

So, ∆U = - ∫F.dx = - ∫Fdxcos180 (since the spring force and extension are in opposite directions)

∆U = - ∫-Fdx

=  ∫F.dx

Since F = 40x - 6x² and x moves from x = 0 to x = 2 m, we integrate thus, ∆U =  ∫₀²F.dx

=  ∫₀²(40x - 6x²).dx

=  ∫₀²(40xdx - 6x²dx)

=  ∫₀²(40x²/2 - 6x³/3)

=  ∫₀²(20x² - 2x³)

= [20x² - 2x³]₀²

= [(20(2)² - 2(2)³) - (20(0)² - 2(0)³)

= [(20(4) - 2(8)) - (0 - 0))

= [80 - 16 - 0]

= 64 J

5 0
3 years ago
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