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2 years ago

Think about whether these ordered pairs represent a function. Then use the drop-

Mathematics

1 answer:

Lostsunrise [7]2 years ago

4 0

Answer: All x-coordinates are different, so this relation is a function.

Having the same y value more than once is not a problem for a function.

"This (does not/does) represents a function because different (x values/y values) can have the same (x values/y values)."

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

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dolphi86 [110]

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2 years ago

Read 2 more answers

For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?

Arlecino [84]

Answer:

For $c=\frac{1}{7}$ the function f(x) is continuous on $(-\infty,\infty)$ .

Step-by-step explanation:

We have the following function

$f(x) = \left\{ \begin{array}{ll} cx^2+5x & \quad x$

For the function f(x) to be continuous on $(-\infty,\infty)$ it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

$\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x)$ ,

which holds if and only if

$c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6$

namely if $c=\frac{1}{7}$ .

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2 years ago