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3 years ago

13

Help me do the rest somebody pleaseeeeee

1 answer:

Len [333]3 years ago

7 0

Answer:

so it's like the push factors are the ones that makes you want to leave that place cuz of negative life style are pull factors are like the positive things about that place that it makes you want to stay there.. I have posted the answers in the other one check it

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What is the vertex of x^2

Delvig [45]

Answer:

The vertex is (0,0)

Step-by-step explanation:

To find the x coordinate of the vertex

x = -b/2a where ax^2 +bx +c

a=1 b=0 c=0

x = -0/2(1) = 0

The y value is found by substituting into the equation

y = (0)^2 =0

The vertex is (0,0)

6 0

3 years ago

10. Determine the measure of each segment. Select the statement that is true.

Pepsi [2]

its A.

Step-by-step explanation:

its B

6 0

2 years ago

A solid lies between planes perpendicular to the x-axis at x=0 and x=3. The cross-sections perpendicular to the axis on the inte

Hatshy [7]

Answer:

V = 9

Step-by-step explanation:

You can see it in the picture.

6 0

3 years ago

According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : $P(X=r) =^nC_r p^r q^{n-r}$

At x = 2

$P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}$

$P(X=2) =8.8009 \times 10^{-7}$

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=0.2360$

8 0

3 years ago

1/7x-5=2 can anyone solve for X?

Vikki [24]

In this equation x = 49.

In order to find this, follow the order of operation of solving equations.

1/7x - 5 = 2 -----> Add 5 to both sides

1/7x = 7 ----> Multiply both sides by 7

x = 49

3 0

3 years ago