Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:
![\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac2n%5Cright%5D%2C%5Cleft%5B%5Cdfrac2n%2C%5Cdfrac4n%5Cright%5D%2C%5Cleft%5B%5Cdfrac4n%2C%5Cdfrac6n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7B2%28n-1%29%7Dn%2C2%5Cright%5D)
Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

where
. Each interval has length
.
At these sampling points, the function takes on values of

We approximate the integral with the Riemann sum:

Recall that

so that the sum reduces to

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

Just to check:

Answer: Approximately 4.7 hours.
Step-by-step explanation:
He rode the bicycle for some time before it broke down and he walked the remaining distance. This means that Jim covered a total of 165 miles by riding at a speed of 35 miles per hour and walking at a speed of 3 miles per hour.
Let x = the distance covered by riding the bicycle.
Let y = the distance covered by walking.
Time = distance /speed
Time he used in riding would be x/35
Time he used in walking would be y/3
Since the entire trip took 7 hours,
x/35 + y/3 = 7
3x + 35y = 735 - - - - - - - - 1
Total miles covered is 165. Therefore,
x + y = 165 - - - - - - - - -- - -2
Substituting x = 165-y into equation 1, it becomes
3(165-y) + 35y = 735
495-3y + 35y = 735
-3y + 135y = 735-495
132y = 240
y = 240/132
y = 1.81m
x = 165 - 1.81 = 163.19
Amount of time that he spent on the bicycle will be
x/35 = 163.19/35
= 4.66
Approximately 4.7 hours.
Answer:
60 different possibilities
Step-by-step explanation:
Number of bikers = 5
Positions = first, second and third
First positions = all 5 riders can take the first spot = 5 possibilities
Second spot = position 1 has been filled hence number of possibilities = ( 5 - 1) = 4
Third spot = position 1 and 2 has been filled ; number of possibilities =. (5 - 2). = 3
Number of possible arrangements :
5 * 4 * 3 = 60 different possibilities
You could rewrite

as

and be tempted to cancel out the factors of

. But this cancellation is only valid when

.
When

, you end up with the indeterminate form

, which is why

is not a zero.