Use a Mohr circle to find the maximum shear stress relative to the axial stress.
Here we assume the axial stress is sigma, the transverse axial stress is zero.
So we have a Mohr circle with (0,0) and (0,sigma) as a diameter.
The centre of the circle is therefore (0,sigma/2), and the radius is sigma/2.
From the circle, we determine that the maximum stress is the maximum y-axis values, namely +/- sigma/2, at locations (sigma/2, sigma/2), and (sigma/2, -sigma/2).
Given that the maximum shear stress is 60 MPa, we have
sigma/2=60 MPa, or sigma=120 MPa.
(note: 1 MPa = 1N/mm^2)
Therefore
100 kN/(pi*d^2/4)=100,000 N/(pi*d^2/4)=120 MPa where d is in mm.
Solve for d
d=sqrt(100,000*4/(120*pi))
=32.5735 mm
Answer:
x = 0, π/4, π, 7π/4
Step-by-step explanation:
sin(2x) = √2 sin x
Use double angle formula.
2 sin x cos x = √2 sin x
Move everything to one side.
2 sin x cos x − √2 sin x = 0
Factor.
sin x (2 cos x − √2) = 0
Solve.
sin x = 0, cos x = ½√2
x = 0, π/4, π, 7π/4
Add up all the sides!
and did you mean 2m or 2cm?
if you meant 2m...
2m = 200cm
so 200cm + 10cm + 45cm = answer
of if you meant 2cm
then 2cm + 10cm + 45cm = answer
Answer:
x = 18
Step-by-step explanation:
Total interior angle of pentagon: 540 degrees
(3x + 23) + (9x - 6) + 95 + 90 + (7x - 4) = 540
19x + 23 - 6 + 95 + 90 - 4 = 540
19x + 17 + 95 + 90 - 4 = 540
19x + 13 + 185 = 540
19x + 198 = 540
19x = 342
x = 18
