Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
Answer:
50
Step-by-step explanation:
I'm sorry but your missing the questions but I found a close answer! Let A be the number of cards Alan has B be the number of cards Bill has C be the number of cards Calvin has Alan had 11 less than 2 1/2 times the number of cards bill has. is 2.5 Alan is 2.5 of bill has minus 11 A=2.5B -11 Calvin has 1 more than 1 1/2 times the number of cards bill has. is 1.5 Calvin is 1.5 of bill has plus 1 C=1.5B + 1 Alan and Calvin have the same number of cards So A=C WE plug in A and C equations and solve for B 2.5B -11 = 1.5B + 1 (subtract 1.5B on both sides) 1B -11 = 1 (Add 11 on both sides) B = 12 If Alan and Calvin have the same number of cards, the number bill has is 12 The number of cards Alan and Calvin each have is 19 Total cards = 12 + 19 + 19 = 50 If Alan, bill, and Calvin have all the cards in the deck then the deck has 50 cards.
No. 4/x will take the form of a hyperbola and is called an inverse function.
