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Gwar [14]
2 years ago
12

9/12 +3/12 =? A. 1 B. 6/12 C. 11/12 D.1/2

Mathematics
2 answers:
Nady [450]2 years ago
7 0

9/12 + 3/12 = 12/12 = 1

Therefore, 1 is your answer.

AveGali [126]2 years ago
5 0

Answer:

Solving \frac{9}{12}+\frac{3}{12} we get 1.

Option A is correct answer.

Step-by-step explanation:

We need to solve \frac{9}{12}+\frac{3}{12}

For solving fractions we need to take LCM of denominators.

The LCM of 12, 12 is 12

So, solving:

\frac{9}{12}+\frac{3}{12}\\=\frac{9*1+3*1}{12}\\=\frac{9+3}{12}\\=\frac{12}{12}\\=1

So, solving \frac{9}{12}+\frac{3}{12} we get 1.

Option A is correct answer.

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Lola walks 4/10 mile to her friends house. then she walks 5/10 mile to the store. how far does she wall in all?
Masteriza [31]
We know that <span>Lola walks 4/10 mile to her friends house. then she walks 5/10 mile to the store. 

To solve the problem we have to use addition. 

4/10 + 5/10 = 9/10 

Lola walks 9/10 miles. </span>
8 0
2 years ago
Read 2 more answers
A sample of students is taken from the school's A honor roll. The school estimates that there are actually 360 students on the A
aliya0001 [1]

Answer:

360 - Y

Step-by-step explanation:

From the information provided in the question, we will understand that the question lacks detailed information.

Given that:

The total number of actual students on the A honor roll = 360

To find the number of students on the A honor roll of 8th graders;

Let denote Y to represent the total number of students who exist on the A honor roll except for the 8th graders.

Then:

The number of 8th graders = all number of students on are on the A honor roll - Y

The number of 8th graders = 360 - Y

If Y is known, then the number of the 8th graders can be fully determined.

5 0
2 years ago
how many such tests would it take for the probability of committing at least one type i error to be at least 0.7? (round your an
drek231 [11]

The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118   .

In the question ,

it is given that ,

the probability of committing at least , type I error is = 0.7

we  have to find the number of tests ,

let the number of test be n ,

the above mentioned situation can be written as

1 - P(no type I error is committed) ≥ P(at least type I error is committed)

which is written as ,

1 - (1 - 0.01)ⁿ ≥ 0.7

-(0.99)ⁿ ≥ 0.7 - 1

(0.99)ⁿ ≤ 0.3

On further simplification ,

we get ,

n ≈ 118 .

Therefore , the number of tests are 118 .

Learn more about Error here

brainly.com/question/17062640

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4 0
11 months ago
Beanbag chairs it normally sell for $36.30 on sale for $32.12 find the percent of discount
Anuta_ua [19.1K]

Answer:


Step-by-step explanation:


5 0
2 years ago
Read 2 more answers
How to answer because I struggle to answer
SpyIntel [72]

5: AA  47=47    36=36  similar

6: SSS   32/16 =2,  24/12 =2,  9/4.5 = 2  similar    

7: SAS  72/53= 1.3,  55=55, 48/12 = 4  not similar

8: SAS  45/15= 3,  54=54,  9/3=3  Similar

9.SAS  20/10 =2,  10/8 = 1.25  not similar

10.SAS  32/14= 2.29, 46=46,  12/7= 1.79  not similar


5 0
3 years ago
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