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Norma-Jean [14]
3 years ago
5

Please help Due asap SHOW a workings please

Mathematics
1 answer:
kiruha [24]3 years ago
8 0

Answer:

A

Step-by-step explanation:

1) first there are a few rules we need to know:

a) the sum of any two sides of a triangle is always larger than the 3rd side

b) the difference between any two sides of a triangle is always smaller than the 3rd side;

hence,

3+4=7

4-3=1

triangle 3,4,5 follows all the rules,

triangle 13,2,11:

11+2=13

the sum of any two sides must always be GREATER than the 3rd side-so this is not an option

triangle 10,4,5

5+4=9

9<10

not an option

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Elanso [62]
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10. $122.50 / 7 lawns = $17.50 per lawn
11. $112.50 / 7.5 hours = $15.00 per hour
$122.50 / 5 hours = $24.50 per hour
Alastair earns more per hour
12. Taryn: 49 more hours ($735 / $15.00)
Alastaie: 30 more hours ($735 / $24.50)
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6 0
2 years ago
What is the equation of the graphed line written in standard form?
Masja [62]

First you'll find the equation of the graphed line in slope-intercept form, y = mx+b, and then from there we'll convert it into standard form, ax+by = c.

To find the slope of the line you could either use the two points on the line or just look and see.

Start from the point farther down, the point on (5,0). Look and see how many units it takes to go up/down to where the point on (0,3) is.

If it goes up, then you are at a positive slope so far. If it goes down, then you are at a negative slope so far. It takes 3 units UP (positive) to go onto the line that (0,3) is on.

Now see how far does it take to go left/right to where the point on (0,3) is. If you have to go left, that means you have a negative; if it goes right then you have a positive. It takes 5 units LEFT (negative) to where (0,3) is.

A positive (up) and a negative (left) make a negative, so your slope is how many units it took to go vertically/how many units it took to go horizontally.

Your slope is -3/5.

Now to solve for b, or the y-intercept, you can look on the graph to see where the point lies on the y-axis (vertical). The point lies on 3 on the y-axis, so your y-intercept is 3.

Since you have the slope and can see the y-intercept of the graphed line, you can make the equation y = mx+b by plugging in -3/5 for the slope and plugging in 3 for b (y-intercept).

y = (-3/5)x+(3)

Remove the parentheses: y = -3/5x+3.

Now to convert from slope-intercept form into standard form, you will have to move everything to the left side and leave only b, or 3.

Add -3/5x to both sides.

3/5x+y = 3

You can't have a fraction in standard form, so multiply everything in the equation by 5.

3x+5y = 15

Answer is:

C. 3x+5y = 15

7 0
3 years ago
Read 2 more answers
Area triangles? it says show work so pls do
coldgirl [10]

\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2} \times (30 \times h) \\  \\  \leadsto \frac{1}{2}   \times 30h \\  \\  \leadsto  \frac{1}{ \cancel{2}} \times  \cancel{30}h \\  \\  \leadsto1 \times 15h \\  \\  \leadsto \: h = 15 \: yd

Therefore, the require height is 15 yd.

\green\starProof:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2}  \times (30 \times 15) \\  \\  \leadsto \frac{1}{ \cancel{2}}   \times  \cancel{450} \\  \\  \leadsto1 \times 225  \\  \\  area = 225  {yd}^{2}

\boxed{ \frak \red{brainlysamurai}}

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dsp73

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