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3 years ago

How would I find all roots to this equation? (3x-1)(x+1)=0

Mathematics

1 answer:

lukranit [14]3 years ago

8 0

$(3x-1)(x+1)=0 =\textgreater 3x-1=0 -->3x=1 --> x=\frac{1}{3} ; x+1=0 =\textgreater x=-1$

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I need help putting correct answers in the yellow boxes.

olasank [31]

Answer:

-5 ± √5² - 4 · 1 · 4

2 · 1

Step-by-step explanation:

ax²+bx+c=0 (quadratic equation)

x= -b ± √b² - 4ac

a= 1

b= 5

c= 4

-5 ± √5² - 4 · 1 · 4

2 · 1

7 0

2 years ago

I need help with number 3

olya-2409 [2.1K]

Answer: He would earn $14

Step-by-step explanation: Since Sam had 11 games but only 9 of them were working just take 11 - 9 which = 2 then take 7 x 2 to get $14

Hope this helps

3 0

3 years ago

Read 2 more answers

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m

Harrizon [31]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

Let $\mu$ = average mg of mercury in compact fluorescent bulbs.

So, Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean mg of mercury = 3.59

$\sigma$ = population standard deviation = 0.18 mg

n = sample of bulbs = 25

So, test statistics = $\frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }$

= 2.50

The value of z test statistics is 2.50.

Now, P-value of the test statistics is given by;

P-value = P(Z > 2.50) = 1 - P(Z $\leq$ 2.50)

= 1 - 0.9938 = 0.0062

Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0

3 years ago

I need help with 9-81 ASAP PLS THIS IS MY HW

Yuri [45]

It is -72 lol. that's pretty basic you know

4 0

3 years ago

Read 2 more answers

Use the drop-down menus to choose steps in order to correctly solve 4k−6=−2k−16−2 for k.

RoseWind [281]

From figure 1: -

From figure 2: 12

From figure 3: 6

From figure 4: -12

From figure 5: -2

Step-by-step explanation:

We need to solve the equation $4k-6=-2k-16-2$ for k.

Solving:

$4k-6=-2k-16-2\\4k-6=-2k-18\\4k=-2k-18+6\\4k=-2k-12\\4k+2k=-12\\6k=-12\\k=\frac{-12}{6}\\k=-2$

So, the options to be selected are:

From figure 1: -

From figure 2: 12

From figure 3: 6

From figure 4: -12

From figure 5: -2

Keywords: Solving equations

Learn more about Solving equations at:

#learnwithBrainly

7 0

3 years ago