How would I find all roots to this equation? (3x-1)(x+1)=0

Mathematics

1 answer:

lukranit [14]3 years ago

8 0

$(3x-1)(x+1)=0 =\textgreater 3x-1=0 -->3x=1 --> x=\frac{1}{3} ; x+1=0 =\textgreater x=-1$

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