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dem82 [27]
3 years ago
7

Vanessa is a set designer. She is working on a period film set in Egypt. She has selected several items for a scene in a palace.

She visits a library and a museum in Cairo to check the authenticity of the items. What responsibility is Vanessa undertaking?
Computers and Technology
2 answers:
BARSIC [14]3 years ago
4 0

C - researching

PLATO

Leona [35]3 years ago
3 0

Answer:

the responsibility of cultural and historical accuracy checking

Explanation:

Vanessa seems to be undertaking the responsibility of cultural and historical accuracy checking. By visiting the library and museum, Vanessa is researching historical data in order to make sure that the items that she has selected match the same type of items that Individuals living in Ancient Egypt times would use as well. This provides both historical and cultural accuracy to the film by representing The citizens of Ancient Egypt as they were in that time.

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What are options in the Advanced tab in the Share Workbook dialog box? Check all that apply.
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All options in the Advanced tab in the Share Workbook dialog box.

  • Don’t keep change history
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  • Track changes for certain amount of days
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<u>Explanation:</u>

In shared workbook in advanced tab it has following options. Based on end user selection changes are applied on shares workbook.

1. Either keep the history for certain period or don’t keep the history on shared workbook.

2. On share work Save changes on period schedule (automatically update) or just see other user changes.

3. Before changes are made for share workbook either prompt for save option or last modified saved.

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Answer:

Stick to concrete nouns

Explanation:

The best technique to improve the web search result is that search with the help of keywords. These keywords help in searching the required results from search engines.

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Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

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