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serg [7]
3 years ago
11

Discuss the pros and cons of tombstoning versus multitasking. Why do you think Microsoft chose tombstoning?

Computers and Technology
1 answer:
finlep [7]3 years ago
6 0

Answer:

Multitasking is the capacity of a computer to manage multiple tasks simultaneously. Tombstoning is being used on Windows mobile but when it is not being used, it is likened with a napping state of an app or program.

Explanation:

Multitasking is the capacity of a computer to manage multiple tasks simultaneously. Tombstoning is being used on Windows mobile but when it is not being used, it is likened with a napping state of an app or program.

The main difference between tombstoning & multitasking is that one uses memory and one doesn't. One of big issues with the Android operating system is that when the client feels they have left the program, apps remain in the background utilizing resources.

Telephones with multitasking abilities use vital resources and have a shorter batter life than telephones without multitasking. This is the major reason why Microsoft is choosing to use tombstoning rather than multi tasking on phones.

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Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positiv
elena-s [515]

Answer:

PART ONE

  1. import java.util.Scanner;
  2. public class CountToLimit {
  3.    public static void main(String[] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        int countLimit = 0;
  6.        int printVal = 0;
  7.        // Get user input
  8.        System.out.println("Enter Count Limit");
  9.        countLimit = scnr.nextInt();
  10.        do {
  11.            System.out.print(printVal + " ");
  12.            printVal = printVal + 1;
  13.        } while ( printVal<=countLimit );
  14.        System.out.println("");
  15.        return;
  16.    }
  17. }

PART TWO

  1. import java.util.Scanner;
  2. public class NumberPrompt {
  3.    public static void main (String [] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        System.out.print("Your number < 100: ");
  6.       int  userInput = scnr.nextInt();
  7.      do {
  8.           System.out.print("Your number < 100: ");
  9.           userInput = scnr.nextInt();
  10.       }while (userInput>=100);
  11.        System.out.println("Your number < 100 is: " + userInput);
  12.        return;
  13.    }
  14. }

Explanation:

In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14

In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10

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What is the different between the patch Tool and the Headling Brush tool?​
KonstantinChe [14]

Answer:

Explanation:

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3 years ago
Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

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