Answer:
a_n = 2^(n - 1) 3^(3 - n)
Step-by-step explanation:
9,6,4,8/3,…
a1 = 3^2
a2 = 3 * 2
a3 = 2^2
As we can see, the 3 ^x is decreasing and the 2^ y is increasing
We need to play with the exponent in terms of n
Lets look at the exponent for the base of 2
a1 = 3^2 2^0
a2 = 3^1 2^1
a3 = 3^ 0 2^2
an = 3^ 2^(n-1)
I picked n-1 because that is where it starts 0
n = 1 (1-1) =0
n=2 (2-1) =1
n=3 (3-1) =2
Now we need to figure out the exponent for the 3 base
I will pick (3-n)
n =1 (3-1) =2
n =2 (3-2) =1
n=3 (3-3) =0
The graph of the solution set for the inequality can be seen below.
<h3>How to graph the solution set?</h3>
Here we have the inequality:
3x - 2y < -12
If we isolate y, we get:
3x + 12 < 2y
(3x + 12)/2 < y
(3/2)x + 6 < y
Now, we just need to graph the line y = (3/2)x + 6 with a dashed line (because the points on the line are not solutions).
And then we need to shade the region above the line.
The graph of the solution set can be seen below.
If you want to learn more about inequalities:
brainly.com/question/18881247
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Answer:
since each item costs rs1263 we say
rs1263×22
27786
this means he spent rs27786
Her we now say rs47500-rs27786
=rs19714
This is to say that he has rs19714 left with him.
Answer:
Step-by-step explanation:
