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Debora [2.8K]
3 years ago
11

Simplify 8n + 3 - 4 + 4n show work pls

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0

Answer:

11n

Step-by-step explanation:

8n + 3= 11n

11n-4=7n

+4n=11n

Zepler [3.9K]3 years ago
6 0

Answer:

1.Subtract the numbers:

8n+3-4+ 4n

8n-1+ 4n

2.Combine like terms

8n-1+4n

12n-1

solution

12n-1

Step-by-step explanation:

I hope this can help you!!

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Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic
nydimaria [60]

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

4 0
3 years ago
What are the steps of factoring (5m-2)^2-(3m-4)^2 ?
Svetlanka [38]
We use the formula a^2 - b^2 = ( a - b )( a + b );
We have a = 5m - 2 and b = 3m - 4;
<span>(5m-2)^2-(3m-4)^2 = (5m - 2 -3m + 4) x (5m-2 + 3m - 4) = (2m + 2)(8m - 6) = 2(m +1) x 2(4m - 3) = 4(m+1)(4m-3);

</span>
6 0
3 years ago
apex if you put down 15% on a $9000 car and pay monthly payments of $189.40 for 48 months what is the total price of the car
defon

The total amount payable for the car if you put a down 15% on a $9000 car and payment of $189.40 for 48 months will be:

Amount=(15/100×9000)+(189.40×48)

=1350+9091.2

=10,441.2

The total amount of money paid for the car after a period of time will be $10,441.2



6 0
3 years ago
What is the value of the 6 in 861
NISA [10]

Answer:

tens-or 60

Step-by-step explanation:

the 1 is in the ones place the 6 is in the tens place and the 8 is in the hudreths place.

6 0
3 years ago
Read 2 more answers
John is buying food for his cat, Fluffy. Fluffy LOVES a fancy wet food which costs $1.50 per day. Fluffy will also tolerate dry
Vedmedyk [2.9K]

Answer:

The answer is below

Step-by-step explanation:

Let x represent the number of days that fluffy eats wet food in a week and y represents the number of days that fluffy eats dry food in a week.

Hence:

x + y = 7                    (1)

Also, John wants to spend at most $9.00 on cat food each week. Hence:

1.5x + 0.75y ≤ 9       (2)

The list of possible points after solving graphically are:

(0,7), (6,0), (0,12) and (5, 2). If x,y > 0, then the point that satisfies the inequality is:

(5, 2) i.e. 5 wet food and 2 dry food

5 0
3 years ago
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