Question

Find the equation of a straight line passing through the point (0,1) which is perpendicular to the line y=-2x+2

Answer 1

Answer:

y = $\frac{1}{2}$ x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x + 2 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-2}$ = $\frac{1}{2}$

The line crosses the y- axis at (0, 1) ⇒ c = 1 , then

y = $\frac{1}{2}$ x + 1 ← equation of perpendicular line