How many gigameters is 93 million miles and how? Plz Show your work.

What is 5/8ths of 48 , I need help I really don't get it

Bess [88]

$\frac58\ \cdot\ 48=\\=\frac58\ \cdot\ \frac{48}{1}=\\=\frac51\ \cdot\ \frac61=\\=5\ \cdot\ 6=\\=30$

6 0

3 years ago

A car uses 1 gallon of gasoline for every 25 miles driven. At the start of a trip the tank was full of gasoline. After driving 5

dezoksy [38]

Answer:

d = 22 - x / 25

Step-by-step explanation:

The first thing is to calculate the tank capacity, we know that per gallon 25 miles are traveled and at 500 miles there were still two gallons, therefore:

500 miles / 25 miles / gallon = 20

and how there were still 2

20 + 2 = 22

the tank has a 22 gallon capacity

Therefore the equation would be:

d = 22 - x / 25

where x is the number of miles traveled.

for example, if they have traveled 500 miles it would be:

d = 22 - 500/25 = 22 - 20

d = 2 gallons

we can verify that it is correct because it is what the statement says

8 0

3 years ago

One pound of candies costs $3.50. How much will we have to pay for 3 lb?

Romashka-Z-Leto [24]

Answer: 10.50 dollars

Step-by-step explanation:

3.50 x 3 = 10.50

8 0

3 years ago

________ are ratios that name the same comparison

Gre4nikov [31]

<span>Equivalent ratios are ratios that name the same comparison. Meanwhile, equivalent fractions </span><span>are fractions that name the same amount or part. Equivalent ratios and equivalent fractions are similar in that the two quantities refer to ratios and fractions that ultimately have the same value but are expressed in a different way. For example, 48/64 is equivalent to 72/96, both have the value of 3/4. </span>

4 0

3 years ago

Read 2 more answers

A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus

aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject $H_0: \mu= 1.6$ , we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis $H_0:\mu= 1.6$ (the null hypothesis always have the equal sign).

We have to test the null hypothesis

$H_0:\mu= 1.6$

The significance level for this test is 0.05

Calculation of the t-statistic:

$t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47$

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject $H_0: \mu= 1.6$ , we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0

2 years ago