Answer:
The area of Postage Stamp measured in ![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Step-by-step explanation:
Postage Stamp is in Rectangular or a Square shape.
Size of the stamp is very small that is in centimeter not in meter.
We have,
![\textrm{Area of Rectangle}= Length\times Breadth= cm\times cm=cm^{2} \\\textrm{Area of Square}= side\times side= cm\times cm=cm^{2} \\](https://tex.z-dn.net/?f=%5Ctextrm%7BArea%20of%20Rectangle%7D%3D%20Length%5Ctimes%20Breadth%3D%20cm%5Ctimes%20cm%3Dcm%5E%7B2%7D%20%5C%5C%5Ctextrm%7BArea%20of%20Square%7D%3D%20side%5Ctimes%20side%3D%20cm%5Ctimes%20cm%3Dcm%5E%7B2%7D%20%5C%5C)
YOUR ANSWER IS IN THE ATTACHMENT PLZZ REFER TO THE ATTACHMENT
I think it’s b or c mostly b
Answer:
b g and e
Step-by-step explanation:
Answer:
C = 5.
Step-by-step explanation:
First, you need to remember that:
For the function:
h(x) = Sinh(k*x)
We have:
h'(x) = k*Cosh(k*x)
and for the Cosh function:
g(x) = Cosh(k*x)
g'(x) = k*Cosh(k*x).
Now let's go to our problem:
We have f(x) = A*cosh(C*x) + B*Sinh(C*x)
We want to find the value of C such that:
f''(x) = 25*f(x)
So let's derive f(x):
f'(x) = A*C*Sinh(C*x) + B*C*Cosh(C*x)
and again:
f''(x) = A*C*C*Cosh(C*x) + B*C*C*Sinh(C*x)
f''(x) = C^2*(A*cosh(C*x) + B*Sinh(C*x)) = C^2*f(x)
And we wanted to get:
f''(x) = 25*f(x) = C^2*f(x)
then:
25 = C^2
√25 = C
And because we know that C > 0, we take the positive solution of the square root, then:
C = 5