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Lilit [14]
3 years ago
9

Find 270% of 25 use th proportion strategy (nearest tenth)

Mathematics
2 answers:
icang [17]3 years ago
3 0

Answer:

67.5

Step-by-step explanation:

or 60 tens, 7 ones, 5 tenths

aleksley [76]3 years ago
3 0
270% of 25 is 67.5
just put it in the calculator
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3 times the first of three consecutive odd integers is 3 more than twice the third? what is the third integer
fenix001 [56]

Answer:

15

Step-by-step explanation:

The difference between consecutive integers is 1.

The difference between consecutive odd integers is 2.

Let the smallest odd integer be x.

Then the next greater one is x + 2. The greatest one is x + 4.

"3 times the first" is 3x

"twice the third" is 2(x + 4)

"3 times the first of three consecutive odd integers is 3 more than twice the third"

3x = 2(x + 4) + 3

3x = 2x + 8 + 3

x = 11

The smallest integer is 11.

x + 4 = 11 + 4 = 15

The greatest one is 15.

4 0
3 years ago
Simplify: 3/5x + x<br> Where 3 over 5 x plus x
hoa [83]
3/(5x) + x = 3/(5x) + x/1 * (5x)/(5x)
= 3/(5x) + 5x²/5x
= (3+5x²) / 5x
4 0
3 years ago
Read 2 more answers
For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
Vesnalui [34]

Answer:

For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

4 0
3 years ago
What is the least common denominator used to add the fractions 1/18 and 5/12
Ne4ueva [31]

Answer:

6

Step-by-step explanation:

Im right

7 0
3 years ago
Hunter's time for the 100-meter freestyle event was 57.9 seconds. His time for the second half of the race was 4.7 seconds slowe
Ratling [72]

Answer:

Step-by-step explanation:

Time for first race 57.9seconds

x=time for first half of race

x-4.7=second half of race

Equations is

x + (x-4.7)=57.9

2x-4.7=57.9

2x=57.9+4.7

2x=62.6

x=31.3

Check answer

31.3 + (31.3-4.7)=57.9

31.3 +26.6=57.9

57.9=57.9

6 0
3 years ago
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