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olga55 [171]
3 years ago
8

Solve for x. Round to the nearest tenth, if necessary. 5.5 D 61° х FPlease help​

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

Step-by-step explanation:

take 61 degree as reference angle

using cos rule

cos 61=adjacent/hypotenuse

0.48=5.5/x

x=5.5/0.48

x=11.45

x=11.5

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Two models of cellular telephones, red and blue, are stored in boxes. One box weighs twelve pounds and contains four of the red
GenaCL600 [577]
First, make a equation in which r= red and b=blue.

So, since in the first box it has 4 red models and one blue model equaling 12,

the first equation looks like 4r+b=12.

The second equation looks like 2r+b=8.

What you would do is try and first solve for r by getting rid of b.

Since both equation has a positive b, you would make one equation have a negative b by multiplying the whole equation by -1.

-1*(2r+b=8)= -2r-b=-8

Add.

4r+b=12
+(-2r-b=-8)

2r=4
r=2

Then, you plug in 2 for the r for any of the original equations.

4(2)+b=12

8+b=12

b=4

or

2(2)+b=8

4+b=8
b=4

So, the red models weigh 2 pounds while the blue models weigh 4.



5 0
3 years ago
Dana is playing a game where she loses 75 points every time she rolls an even number. She starts with 0 points. Then she rolls a
slavikrds [6]

Answer:

-375

Step-by-step explanation:

-75 * 5

= -375.

3 0
3 years ago
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

Center = (5, -4)

and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10

The standard form of equation of circle is:

(x-h)^{2}+(y-k)^{2}=r^{2}

where h and k are the coordinates of the center. So putting in the value:

(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100

8 0
3 years ago
What is the value of x and y?
Pavel [41]

Answer:

x=\boxed{2}

y=\boxed{4}

Step-by-step explanation:

\begin{cases} y= 6x-8... (1)\\\\y=-3x+10...(2)\end{cases}

From equations (1) & (2), we find:

6x - 8 = - 3x +10

\therefore 6x+3x = 8+10

\therefore 9x = 18

\therefore x =\frac{18}{9}

\therefore x = 2

Plug x = 2 in equation (1)

y = 6(2)-8 = 12-8 =4

So,

x=\boxed{2}

y=\boxed{4}

6 0
3 years ago
Read 2 more answers
the volume of a prism changes from 20 to 540 after a dilation. What was the scale factor of the dilation?
pashok25 [27]
Hello!

You find what they did between the prisms by dividing the second prism by the first prism

540 / 20 = 27

The scale factor is 27

The answer is 27

Hope this helps!
5 0
3 years ago
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