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nlexa [21]
3 years ago
14

Why efficiency of electrons causes negative charge​

Physics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

Since opposite charges attract each other, the negatively charged electrons are attracted to the positively charged protons. ... Together, all of the electrons of an atom create a negative chargethat balances the positive charge of the protons in the atomic nucleus.

Explanation:

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An incompressible fluid flows at .252 m/s through a 44 diameter (circular cross section) pipe. The pipe widens to a square cross
Serggg [28]

ANSWER:

The easiest way to get a fairly accurate measure of your water flow rate is to time yourself filling up a bucket. So for example if you fill up a 10 litre bucket in 1.5 minutes, then your flow rate will be: 10/1.5 = 6.66 Litres per minute.

7 0
2 years ago
A person walks 12 meters to the west and then 16 meters back to the east. what is the distance covered and the direction of disp
devlian [24]
The distance is 28 meters and the direction of displacement is East I think
6 0
3 years ago
Two projectile launchers are beside one another on level ground. Both launchers are directed at the same angle with respect to g
kakasveta [241]

Answer:

(a) Projectile B will travel 4 times as far as projectile A prior to landing

Explanation:

Initial velocity = v

Angle at which the projectile is shot at = θ

g = Acceleration due to gravity

Range of a projectile is given by

R=\frac {v^{2}\sin 2\theta}{g}

When Initial velocity = v

R_A=\frac{v^{2}\sin 2\theta}{g}

When Initial velocity = 2v

R_B=\frac{(2v)^{2}\sin 2\theta}{g}\\\Rightarrow R_B=\frac{4v^2\sin 2\theta}{g}

Dividing the equtions, we get

\frac{R_A}{R_B}=\frac{\frac{v^{2}\sin 2\theta}{g}}{\frac{4v^2\sin 2\theta}{g}}

Here, the angle at which the projectiles are fired at are equal.

\frac{R_A}{R_B}=\frac{1}{4}\\\Rightarrow R_B=4R_A

Hence, projectile B will travel 4 times as far as projectile A prior to landing

7 0
3 years ago
For atomic hydrogen, the Paschen series of lines occurs when nf = 3, whereas the Brackett series occurs when nf = 4 in the equat
zvonat [6]

Answer:

(\lambda_{max} )_{brackett} < (\lambda_{min} )_{paschen}

So the two wavelength range will over lap

Explanation:

The Rydberg equation is given by

\frac{1}{\lambda} =\frac{2\pi mk^2e^4}{h^3c} t (\frac{1}{n^2_f}-\frac{1}{n^2_i}  )

m is the mass of electron

k = 1/4π∈₀

∈₀ = is the permitivity of free space

e is the charge of electron

h is the plank constant

c is the speed of light in vaccum

z is the atomic number = 1

\frac{1}{\lambda} =R (\frac{1}{n^2_f}-\frac{1}{n^2_i}  )

where R is the  Rydberg constant = 1.097373 × 10⁷m⁻¹

For  Paschen series of H spectrum

n_f = 3

n_i = 5,6,7 ...

in Paschen series of H spectrum

The maximum wavelength occur for n_i = 4

\frac{1}{\lambda_m_a_x } =(1.097373 \times 10^7)(\frac{1}{9} - \frac{1}{16} )\\\\\lambda_m_a_x=1874.6nm

The minimum wavelength occur for n_i = ∞

\frac{1}{\lambda_m_i_n } =(1.097373 \times 10^7)(\frac{1}{9} - \frac{1}{_o_o} )\\\\\lambda_m_a_x=820.14nm

The brackett series of H spectrum

The maximum wavelength occur for n_i = 4

\frac{1}{\lambda_m_a_x } =(1.097373 \times 10^7)(\frac{1}{16} - \frac{1}{25} )\\\\\lambda_m_a_x=4050.05nm

The minimum wavelength occur for n_i = ∞

\frac{1}{\lambda_m_i_n } =(1.097373 \times 10^7)(\frac{1}{16} - \frac{1}{_o_o} )\\\\\lambda_m_a_x=1458.03nm

(\lambda_{max} )_{brackett} < (\lambda_{min} )_{paschen}

So the two wavelength range will over lap

8 0
3 years ago
A theme park creates a new kind of water wave pool with large waves caused by constructive interference. There are two wave gene
melomori [17]

Answer:

10.0 m

Explanation:

Since there is no amplitude at the point of the swimmer, we have destructive interference.

So, the path difference ΔL = L₂ - L₁ where L₁ = swimmer's shorter distance from one generator = 9.0 m and L₂ = swimmer's longer distance from the other generator = 14.0 m.  ΔL = 14.0 m - 9.0 m = 5.0 m

Also, since we have destructive interference, ΔL = (n + 1/2)λ where n = number of wavelengths and λ = wavelength of waves

For maximum wavelength, n = 0

So, ΔL = (n + 1/2)λ

ΔL = (0 + 1/2)λ

ΔL = λ/2

λ/2 = ΔL

λ = 2ΔL

λ = 2 × 5.0 m

λ = 10.0 m

So,  the longest wavelength that will produce this interference pattern is λ = 10.0 m

8 0
3 years ago
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