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3 years ago

24 POINTS!!!!!!!!!!!!!!!

2 answers:

7 0

Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880

Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000

Lost Energy = 5880 - 3000 = 2880 J

In short, Your Answer would be 2880 Joules

Hope this helps!

ss7ja [257]3 years ago

6 0

Your Answer would be 2880 Joules

I took the test on K12

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What is the relationship between inertia and mass?

ivann1987 [24]

Answer:

Explanation:

The greater the mass, the greater the inertia, and vice versa.

Remark: This means that a more massive object has a greater tendency to resist a change in its state of rest or motion.

8 0

3 years ago

Based on the following equation, answer the questions below. ρ = (2γϕ + ψ)/rg where ρ [=] moles per cubic foot [mol/ft3] γ [=] j

AlekseyPX

1) Fundamental units of $\Psi$ are $[\frac{mol}{m\cdot s^2}]$

2) Fundamental units of $\Phi$ are $[\frac{mol}{m^3}]$

Explanation:

The equation for the variable $\rho$ is

$\rho =\frac{2\gamma \Phi+\Psi}{rg}$

where we have:

$\rho$ measured in $[\frac{mol}{ft^3}]$

$\gamma$ measured in $[\frac{J}{kg}]$

$r$ measured in $[in]$

$g$ measured in $[\frac{m}{s^2}]$

We can re-write the equation as

$\rho rg = 2\gamma \Phi + \Psi$

And we notice that the units of the term on the left must be equal to the units of the term on the right.

This means that:

1) First of all, $\Psi$ must have the same units of $\rho r g$ . So,

$[\rho r g]=[\frac{mol}{ft^3}][in][\frac{m}{s^2}]$

However, both ft (feet) and in (inches) are not fundamental dimensions: this means that they can be expressed as meters. Therefore, the fundamental units of $\Psi$ are

$[\Psi]=[\frac{mol}{m^3}][m][\frac{m}{s^2}]=[\frac{mol}{m\cdot s^2}]$

The term $2\gamma \Phi$ must have the same units of $\Psi$ in order to be added to it. Therefore,

$[\gamma \Phi] = [\frac{mol}{m\cdot s^2}]$

We also know that the units of $\gamma$ are $[\frac{J}{kg}]$ , therefore

$[\frac{J}{kg}][\Phi]= [\frac{mol}{m\cdot s^2}]$

And so, the fundamental units of $\Phi$ are

$[\Phi]= [\frac{mol\cdot kg}{J\cdot m\cdot s^2}]$

However, the Joules can be written as

$[J]=[kg][\frac{m^2}{s^2}]$

Therefore

$[\Phi]= [\frac{mol\cdot kg}{(kg \frac{m^2}{s^2})\cdot m\cdot s^2}]=[\Phi]= [\frac{mol}{m^3}]$

#LearnwithBrainly

7 0

3 years ago

Prove dimensionally that: PV=RT

Oduvanchick [21]

Ideal Gas Law PV = nRT

THE GASEOUS STATE
Pressure  atm
Volume  liters
n  moles
R  L atm mol^-1 K^-1
Temperature  Kelvin

pv = rt

divide both sides by v
pv/v = rt/v

p = rt/v

answer: p = rt/v

Ideal Gas Law: Density

PV = NRT
PV = mass/(mw)RT

mass/V = P (MW)/RT = density

Molar Mass:
Ideal Gas Law PV = NRT
PV = mass/(MW) RT
MW = mass * RT/PV

Measures of Gases:
Daltons Law of Partial Pressures; is the total pressure of a mixture of gases equals the sum of the partial pressures of the individual gases.

Total = P_ A + P_ B

P_ A V = n_ A RT

P_ B V = n_ B R T

Partial Pressures in Gas Mixtures:
P_ total = P_ A + P_ B
P_ A = n_ A RT/V P_ B = n_ B RTV

P_ total = P_ A + P_ B = n_ total RT/V

For Ideal Gasses:

P_ A = n_ A RT/V P_ total = n_ toatal RT/V

P_ A/P_ total = n_ A RTV/n_ total RTV

= n_ A/n_ total = X_ A

Therefore, P_ A = X_ A P_ total.

PV = nRT

P pressure

V volume

n Number of moles

R Gas Constant

T temperture (Kelvin.).

Hope that helps!!!!!! Have a great day : )

4 0

3 years ago

Science is the process of asking scientific questions about which of the following?

Eva8 [605]

the answer to your question would be D.

4 0

3 years ago

Read 2 more answers

Identify some of the effects of urbanization

dangina [55]

Answer: Heyyyyyyyyyyyyyy

here you goo

"some of the effects of urbanization"

Poor air and water quality, insufficient water availability, waste-disposal problems, and high energy consumption are exacerbated by the increasing population density and demands of urban environments

"hope this helps"

4 0

3 years ago