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3 years ago

24 POINTS!!!!!!!!!!!!!!!

2 answers:

7 0

Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880

Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000

Lost Energy = 5880 - 3000 = 2880 J

In short, Your Answer would be 2880 Joules

Hope this helps!

ss7ja [257]3 years ago

6 0

Your Answer would be 2880 Joules

I took the test on K12

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4 years ago

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3 years ago

Light passes through a 0.15 mm-wide slit and forms a diffraction pattern on a screen 1.25 m behind the slit. The width of the ce

Elena L [17]

Answer:

The value is $\lambda = 900 \ nm$

Explanation:

From the question we are told that

The width of the slit is $a = 0.15 \ mm = 0.00015 \ m$

The distance of the screen from the slit is D = 1.25 m

The width of the central maximum is $y = 0.75 \ cm = 0.0075 \ m$

Generally the width of the central maximum is mathematically represented as

$y = \frac{m * D * \lambda}{a}$

Here m is the order of the fringe and given that we are considering the central maximum, the order will be m = 1 because the with of the central maximum separate's the and first maxima

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3 years ago