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Studentka2010 [4]
2 years ago
7

Gamma ray technology can be used to do which of the following?

Physics
1 answer:
Rudiy272 years ago
5 0

Answer:

b

Explanation:

radiation can treat tumors.

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The noble gas neon is used for filling neon signs. Like other noble elements, it has a full octet (complete outer energy level)
DanielleElmas [232]

Answer:

C. unlikely to combine with other elements.

Explanation:

In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.

Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.

Noble gases are chemical elements with eight valence electrons and as such have a full octet. Some examples are argon, neon, etc.

Hence, the full octet makes the gas (neon) unlikely to combine with other elements.

7 0
3 years ago
A metal ball has a mass of 2.05 kg and a volume of 6.8 cm. What is its density? Remember
kogti [31]

Answer:

the density is 0.301 :)

7 0
3 years ago
If a wave has a speed of 12 m/s and a frequency of 4hz what is its wavelength
ELEN [110]
Apply:
wavelength = speed of wave / frequency
wavelength = 12 m/s / 4 Hz = 48 m
6 0
3 years ago
Which are characteristics of concave mirrors? Check all that apply.
aalyn [17]

Answer:

the answers are 1 2 and 5!

5 0
3 years ago
Two 0.40 kg soccer ball collide elastically in a head-on collision. The first ball starts at rest, and the second ball has a spe
yulyashka [42]

Explanation:

Mass of two soccer balls, m_1=m_2=0.4\ kg

Initial speed of first ball, u_1=0

Initial speed of second ball, u_2=3.5\ m/s

After the collision,

Final speed of the second ball, v_2=0

(a) The momentum remains conserved. Using the conservation of momentum to find it as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v_1 is the final speed of the first ball

0.4\times 0+0.4\times 3.5=0.4v_1+0.4\times 0

0.4\times 3.5=0.4v_1

v_1=3.5\ m/s

(b) Let E_1 is the kinetic energy of the first ball before the collision. It is given by :

E_1=\dfrac{1}{2}mu_1^2

E_1=\dfrac{1}{2}\times 0.4\times 0

It is at rest, so, the kinetic energy of the first ball before the collision is 0.

(c) After the collision, the second ball comes to rest. So, the kinetic energy of the second ball after the collision is 0.

Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
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