Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that 
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.




IQ scores of at least 130.81 are identified with the upper 2%.
I will help you but I need to know what you need help with , find the area or volume?
Answer: The mean is 9 cups, the median is 6 cups, and the total is 27.
Step-by-step explanation:
To calculate the mean, add up all values and divide by the amount of all the values: 3 + 6 + 18 = 27, 27/3 = 9. The median is the middle number, which is 6 in the set 3, 6, 18 (least to greatest). Finally the total is already 27. Hope this helps, please consider Brainliest (click on the crown).
Answer:
50
Step-by-step explanation: