3 years ago

Can y’all help me out with this

1 answer:

5 0

$(a) P= \frac{A}{e^{rt}} 

(b) e^{rt}= \frac{A}{P} 

ln e^{rt}= ln(\frac{A}{P}), 
rt= ln(\frac{A}{P}), t= \frac{ ln(\frac{A}{P})}{r}, or, t= \frac{ lnA - lnP}{r},
$

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