Answer:
for 48, the prime numbers I have obtained are 2, 3, 2, 2, and 2
Multiply 12 by 37%.
12 × 0.37 = 4.44
B) at least 4
It could also be c... 4.44 is less than 8. But B is the closest answer to 4.44.
The probability the man will win will be 13.23%. And the probability of winning if he wins by getting at least four heads in five flips will be 36.01%.
<h3>How to find that a given condition can be modeled by binomial distribution?</h3>
Binomial distributions consist of n independent Bernoulli trials.
Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))
P(X = x) = ⁿCₓ pˣ (1 - p)⁽ⁿ⁻ˣ⁾
A man wins in a gambling game if he gets two heads in five flips of a biased coin. the probability of getting a head with the coin is 0.7.
Then we have
p = 0.7
n = 5
Then the probability the man will win will be
P(X = 2) = ⁵C₂ (0.7)² (1 - 0.7)⁽⁵⁻²⁾
P(X = 2) = 10 x 0.49 x 0.027
P(X = 2) = 0.1323
P(X = 2) = 13.23%
Then the probability of winning if he wins by getting at least four heads in five flips will be
P(X = 4) = ⁵C₄ (0.7)⁴ (1 - 0.7)⁽⁵⁻⁴⁾
P(X = 4) = 5 x 0.2401 x 0.3
P(X = 4) = 0.3601
P(X = 4) = 36.01%
Learn more about binomial distribution here:
brainly.com/question/13609688
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Answer:
x-intercept: x = -4/3
Step-by-step explanation:
x-intercept when y = 0
-6x + 0 = 8
so
-6x = 8
x = 8/-6
x = -4/3
Answer:
Put them in 2 teams. 18 boys so 9 in each group. 24 girls so 12 in each group.
Step-by-step explanation:
