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Mazyrski [523]
3 years ago
6

Can y’all help me out with this

Mathematics
1 answer:
labwork [276]3 years ago
5 0
(a)  P= \frac{A}{e^{rt}} 

(b) e^{rt}= \frac{A}{P} 

ln e^{rt}= ln(\frac{A}{P}),  
rt=  ln(\frac{A}{P}),   t= \frac{ ln(\frac{A}{P})}{r}, or,   t= \frac{ lnA - lnP}{r},

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siniylev [52]
8*8 - 4*4*pi*(1/2) = 64 - 8*pi
6 0
4 years ago
Pam has 15 candies in her bag. Her mother puts another handful of candies into the bag. Pam counts all the candies and she now h
julsineya [31]

Answer: 15+X=27

Step-by-step explanation: 15+X=27 X Represents How Much More Is Added

8 0
3 years ago
(PLEASE HELP) A contractor has 10 lots for sale to build on. 4 lots are greater than two acres. 6 lots are less than two acres.
charle [14.2K]
Probability that the first lot sold will be less than two acres = number of lots less than two acres / total number of lots = 6/10 = 3/5
 
Probability that the second lot sold will be less than two acres = remaining number of lots less than two acres / remaining total number of lots = 5/9

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8 0
3 years ago
I need help with this is this circumference or areas will mark you brainly if right
Pani-rosa [81]
The question is cut off, but here are the formulas for area and circumference:

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6 0
3 years ago
Find the total amount of money​ (maturity value) that the borrower will pay back on a loan of ​$1 comma 760 at 13 and one half %
bagirrra123 [75]

Answer:

The borrower will pay back $4,136.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

T = E + P.

In this question:

Loan amount of 1760, so P = 1760

Interest rate of 13 and one half, so 13.5%. This means that I = 0.135.

10 years, so t = 10

Interest on the Loan:

E = P*I*t = 1760*0.135*10 = 2376

Total amount:

T = E + P = 2376 + 1760 = 4136

The borrower will pay back $4,136.

4 0
3 years ago
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