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3 years ago

1.) Simplify: y = -8 + 6(x-1)

Mathematics

1 answer:

swat323 years ago

6 0

8+6=14. (X-1=1x)

14•1x

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Find ten solutions to the linear equation to the linear equation 1/2x+y=5

yuradex [85]

Answer:

(0,5), (2,4), (4,3), (6,2), (8,1), (10,0), (12,-1), (14,-2), (16,-3), (18,-4), and (20,-5)

Step-by-step explanation:

The given linear equation is :

$\frac{1}{2} x + y = 5$

$y = - \frac{1}{2} x + 5$

Any ordered pair that satisfies this equation is a solution.

When x=0,

$y = - \frac{1}{2} \times 0 + 5 = 5$

(0,5) is a solution

When x=2,

$y = - \frac{1}{2} \times 2+ 5 = 4$

(2,4) is a solution.

When x=4,

$y = - \frac{1}{2} \times 4+ 5 = 3$

(4,3) is a solution;

When x=6:

$y = - \frac{1}{2} \times 6+ 5 = 2$

(6,2).

When x=8,

$y = - \frac{1}{2} \times 8 + 5 = 1$

Another solution is (8,1)

When x=10,

$y = - \frac{1}{2} \times 10 + 5 = 0$

(5,0) is a solution

When x=12,

$y = - \frac{1}{2} \times 12+ 5 = - 1$

(12,-1) is a solution.

When x=14,

$y = - \frac{1}{2} \times 14+ 5 = - 2$

When x=16, we get:

$y = - \frac{1}{2} \times 16 + 5 = - 3$

When x=18, we get:

$y = - \frac{1}{2} \times 18+ 5 = - 4$

7 0

4 years ago

Music lessons cost$20 pretty week how much do 6 weeks cost

joja [24]

6 weeks × 20 dollars = $120

4 0

3 years ago

Find an equation for the inverse of the following relation.<br><br> y=12x-3

vovikov84 [41]

<h3>Answer:</h3>

<em>Your answer would be y=x+3/12</em>

<h3>Step-by-step explanation:</h3>

Firstly, you'll switch sides of the equation.

Next, add 3 to both sides.

Simplify it.

Then, divide both sides by 12.

Simplify once more.

12y/12 = x/12 + 3/12 --- y= x+3/12

<u>y=x+3/12 would be your answer.</u>

6 0

3 years ago

G(n)=-n^3+3n^2, find g(-4)

Sauron [17]

Answer:

g(-4) = 112

Step-by-step explanation:

Hi there!

$g(n)=-n^3+3n^2$

To find g(-4), replace all n's with -4:

$g(-4)=-(-4)^3+3(-4)^2\\g(-4)=-(-64)+3(16)\\g(-4)=64+48\\g(-4)=112$

I hope this helps!

5 0

3 years ago

Divide the following

vampirchik [111]

$\frac{x^{2} - 4}{x - 8} \div \frac{x - 2}{1}$
$\frac{x^{2} + 2x - 2x - 4}{x - 8} \div \frac{x - 2}{1}$
$\frac{x(x) + x(2) - 2(x) - 2(2)}{x - 8} \div \frac{x - 2}{1}$
$\frac{x(x + 2) - 2(x + 2)}{x - 8} \div \frac{x - 2}{1}$
$\frac{(x - 2)(x + 2)}{x - 8} \div \frac{x - 2}{1}$
$\frac{x - 2}{x - 8}$

The answer is C.

7 0

4 years ago