<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187
</span>
about 23 years
</span></span>
You would have to find the height.
To do this, you cut the triangle from the upper vertex to the base to create two new triangles.
Then you use the Law of Cosines. You could use the google calculator for this by searching “law of cosines calculator” and inputting the values, but in case of a test, the formula is a^2 = b^2 + c^2 - 2bc cosA
If you could provide an example of a triangle, I will gladly help you with the steps! Hope this helped!
Answer:
15.09
Step-by-step explanation:
with reference angle 28°
perpendicular (p) = 8
base (b) = x
Now
tan 28° = p / b
0.53 = 8 / x
x = 8 / 0.53
x = 15.09
Area of triangle = 1/2 ab sin c
Area of triangle = 1/2 (9.2)(11.9) sin (27)
Area of triangle = 24.85 ft²
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Answer: Area - 24.85 ft²
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