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user100 [1]
3 years ago
13

X log(2^(x+2))=8 please help

Mathematics
1 answer:
larisa [96]3 years ago
7 0

Find the domain by finding where the expression is defined.

Interval Notation:

(−∞, ∞)

Set-Builder Notation:

{x|x∈R}

Solve for x:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = −2 + 8 ln (10)/X ln (2)

Solve for X:

Divide each term by log (2^x+2) and simplify.

X = 8/log (2^x+2)

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What is the volume of the entire figure?<br><br> ____cm3
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3 years ago
What is the solution of log (t minus 3) = log (17 minus 4 t)?<br> 4<br> 5<br> 15<br> 20
Tcecarenko [31]

Option A: 4 is the solution

Explanation:

The given expression is \log (t-3)=\log (17-4 t)

We need to determine the solution of the expression.

<u>Solution:</u>

The solution of the expression can be determined by solving the expression for t.

Let us solve the given expression.

Applying the log rule, if \log _{b}(f(x))=\log _{b}(g(x)) then f(x)=g(x)

Thus, we have;

t-3=17-4 t

Adding both sides of the equation by 4t, we get;

5t-3=17

Adding both sides of the equation by 3, we have;

5t=20

Dividing both sides of the equation by 5, we get;

t=4

Hence, the value of t is 4.

Therefore, the solution of the given expression is 4.

Thus, Option A is the correct answer.

3 0
3 years ago
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Find the equation line<br> (5,6), (4,7)
34kurt

Answer:

x+y=11

Step-by-step explanation:

Here we are given two coordinates through which our lines passes through. Now we are going to use the two point form to find the equation of the line.

The two point form is given as

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}

Here we are given two coordinates . Thus replacing them in the formula and simplifying it will give us the equation of the line.

\frac{y-6}{x-5}=\frac{7-6}{4-5}

\frac{y-6}{x-5}=\frac{1}{-1}

(y-6)=-(x-5)

y-6=-x+5

adding x and 6 on both sides we get

x+y=11

Hence this is our equation of the line passing through (5,6) & (4,7)

8 0
3 years ago
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