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user100 [1]
3 years ago
13

X log(2^(x+2))=8 please help

Mathematics
1 answer:
larisa [96]3 years ago
7 0

Find the domain by finding where the expression is defined.

Interval Notation:

(−∞, ∞)

Set-Builder Notation:

{x|x∈R}

Solve for x:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = −2 + 8 ln (10)/X ln (2)

Solve for X:

Divide each term by log (2^x+2) and simplify.

X = 8/log (2^x+2)

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shepuryov [24]

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81.5 = 82 if ur problem said round it out 82 if not put 81.5

Step-by-step explanation:

4 0
3 years ago
Whats 72/20 as a proper fraction... im lazy.
Ivahew [28]

Answer: 72/20 = <u>3 3/5</u>

Step-by-step explanation:

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laura's family is going on a vacation. they will drive 4,180 miles over the next two weeks. about how many miles will they drive
gizmo_the_mogwai [7]

Answer:

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5 0
3 years ago
Jake’s map shows the distance from the Bake Stars Cafe to the restaurant supply store as 3 centimeters. If the scale of the map
Stolb23 [73]

Answer:

The real distance from shop to store is 24 kilometers.

Step-by-step explanation:

Given:

Distance from the Bake Stars Cafe to the restaurant supply store on map = 3 cm

Also Given:

Scale of the map 1 cm = 8 km

We need to find the real distance from the shop to the store.

Solution:

Now we know that;

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8 0
3 years ago
What are the domain and range of the function below? graph
kirill115 [55]

The domain and range of the function is D) Domain: (-∞, ∞); Range: (-∞, ∞)

<h3>How to illustrate the information?</h3>

The domain is the input values, or the x values. We can put in any x values for this function.

Domain : (-∞, ∞)

The range is the output values or the y values. We can get any output values for this function

Range: (-∞, ∞)

Learn more about domain on:

brainly.com/question/2264373

#SPJ1

<u>Complete question:</u>

What are the domain and range of the function below?

A) Domain: (-∞, -5)

Range: (5, ∞)

B) Domain: (-5, -10)

Range: (5, 10)

C). Domain: (-5, 10)

Range: (-10, 5)

D) Domain: (-∞, ∞)

Range: (-∞, ∞)

4 0
1 year ago
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