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3 years ago

X log(2^(x+2))=8 please help

Mathematics

1 answer:

larisa [96]3 years ago

7 0

Find the domain by finding where the expression is defined.

Interval Notation:

(−∞, ∞)

Set-Builder Notation:

{x|x∈R}

Solve for x:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = −2 + 8 ln (10)/X ln (2)

Solve for X:

Divide each term by log (2^x+2) and simplify.

X = 8/log (2^x+2)

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Evaluate x-2 for x = -3.

Vadim26 [7]

X-2 for x=-3
-3-2=-5, add dem negatives

8 0

3 years ago

Can you guys please help me in question 12 A B C

MaRussiya [10]

12a
math: 68/85 * 100 = 80%
science: 70*0.9 = 63 number correct
b. Science
c.48

8 0

3 years ago

7-3x = -x+1<br> Simplify this equation

frozen [14]

Answer:

x=11

Hope this helps :)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type

Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

$\frac{y}{t} = e^{-kt + C} \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt} (A = e^{C})\\y = Ate^{-kt}$

when t = 1 hour, y = 15 grams. So,

$y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}$ (1)

when t = 3 hours, y = 30 grams. So,

$y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k}$ (2)

dividing (2) by (1), we have

$\frac{30}{15} = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}$

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

$A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36$

Substituting A and k into y, we have

$y = 18.36te^{-0.203t}$

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

$y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g$

<u>So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.</u>

3 0

3 years ago

Alex has a collection of sports cards. There are 10 cards in the collection, and 1/5 of them are hockey cards. Alex decides to d

Alborosie

If 1/5 of the cards are hockey cards, there are 2 hockey cards. if he wants to double that amount, he would multiply it by 2, so 2•2=4. The fraction of hockey cards is now is 2/5.

4 0

2 years ago