The x-coordinate of the vertex of a parabola y = ax^2 + bx + c is x = -b / (2a).
Here, a = -3 and b = -10, so the x-coord of the vertex is x = 10 / (2*-3), or
x = 10 / (-6) = -5/3
and so the y-coordinate is y = -3(-5/3)^2 - 10(-5/3) = 25/3
The vertex of this parabola is (-5/3, 25/3). (answer)
Answer:
2
Step-by-step explanation:
16 ^ (1/4)
Rewriting 16 as 2^4
2^4 ^ 1/4
We know that a^b^c = a^(b*c)
2 ^ (4*1/4)
2 ^1
2
Answer:
x=5+√35
x=5-√35
i ngrenë ne fuqi me pas i zbresim numrat
I think it's b
Hope I could help
Answer:
the answer is b 1.19p+3.18<10.00