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RoseWind [281]
3 years ago
8

Elena bouggt 8 tokens for $4.40. At this rate: How many tokens could she buy with $6.05? Do not include units (tokens) in your a

nswer.​
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0
She could buy 11 tokens. To find this, you divide 4.40 by 8 to find the price for one token, which would be $0.55 each. Then you divide 6.05 by 0.55 to find how much you can get with that much money which would be 11.
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your patient has a 2500 cc bag of irrigation solution hanging, and 750 cc of fluid has been infused. what percentage of irrigati
nlexa [21]

Answer:  30%

Step-by-step explanation:

Given : Patient has a 2500 cc bag of irrigation solution hanging.

Irrigation has been infused = 750cc

Then, the percentage of irrigation solution has been infused :

\dfrac{\text{ fluid infused}}{\text{Total irrigation solution}}\times100\\\\=\dfrac{750}{2500}\times100\\\\= 30\%

Hence, the percentage of irrigation solution has been infused = 30%

6 0
3 years ago
The numbers of students in the four sixth-grade classes at Northside school are 26,19,34 and 21. Use properties to find the tota
san4es73 [151]
Basically there are 3 addition properties and they are associative property, identity property, and commutative property. 

Commutative property is just changing the order of the addends. Example: 26+19+34+21= 21+34+19+26

Identity Property is just adding a 0 to the number that doesnt change anything. Example: 26+19+34+21 +0 = 100

Associative property is just changing the grouping of the addends. Example: (26+19) + (34+21) 
6 0
3 years ago
D=ABC for A solve for A
Dafna1 [17]
A = D/BC. In order to isolate A, all you do is divide by BC
7 0
3 years ago
4) What is the correct unit for the following measurement?
pogonyaev
Meters is the correct answer
6 0
3 years ago
Evaluate the series 4 – 2 + 1 – 0.5 + 0.25 to S10. Round to the nearest hundredth.
aleksklad [387]
The initial term of this geometric series is 4, and the common ratio is -1/2. The sum is given by

S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}\\\\S_{10}=4\cdot \dfrac{(-\frac{1}{2})^{10}-1}{-\frac{1}{2}-1}=4\cdot \dfrac{(\frac{1}{1024}-1)}{(-\frac{3}{2})}\\\\=\dfrac{8}{3}\cdot \dfrac{1023}{1024}=\dfrac{341}{128}

The sum is approximately 2.66.
4 0
3 years ago
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