Consider the arithmetic series 
Let t=1 in the given series, we get
first term = 
= 3-4 = -1.
Let t=2 in the given series, we get
second term = 
= 
Let t=3 in the given series, we get
third term = 
Now, let t=18 in the given series, we get
last term = l = 
We get the series as
-1, 2, 5,..... 50
Sum = 
= 
= 
= 441
Therefore, the sum of the given arithmetic series is 441.
4/5 is the same as 80% or .80, so it's larger than 76% and .77
Answer: We will write ‘3’ in the second space. Therefore, the final number must be 2. 6 ÷ 3 = 2. There is a second way that we could use inverse operations to write this multiplication as a division
Step-by-step explanation:
It is given that two angles are congruent so that means that ASA is the answer.
Hope this helps :)
The base will have the greatest area for a given perimeter if it is square. If the edge of the square base has length x (in feet), then the total material requirement in square feet is
.. m = x^2 +(4/x^2)*(4x)
.. m = x^2 +16/x
This will have a minimum where dm/dx = 0.
.. dm/dx = 2x -16/x^2 = 0
.. x^3 = 8 . . . . . . . . . . . . . . . multiply by x^2/2 and add 8
.. x = 2
The tank is 2 feet square and 1 ft high.
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You will note that it is half the height of a cube that has double the volume. This is the generic solution to all minimum cost open-top box problems. Actually, the costs of pairs of opposite sides are equal to each other and to the cost of the base. If material costs are not identical in all directions, that is the more generic solution.
