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natka813 [3]
3 years ago
9

What is the median of the set of data

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

The median average is the middle number in a set of data , when the data has been written in ascending size order. If there is an even number of items of data, there will be two numbers in the middle. The median is the number that is half way between these two numbers.

I hope it's helpful!

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What is the common difference between the terms in the following sequence?
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Answer:

-6

Step-by-step explanation:

17-6=11

11-6=5

5-6=-1

-1-6=-7

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Elena has some bottles of water that each holds 17 fluids ounces.
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W=17

Step-by-step explanation:

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The in center is the center of the circle of a triangle
Lana71 [14]

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inscribed

Step-by-step explanation:

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2 years ago
Find the measure of the segment indicated.
julsineya [31]
Answer is QM = 18

You can find the length of QM by using Pythagorean theorem. See the attachment.

It is a quadrilateral with 4 equal congruent sides.

If SP = 30, so do the other 3 sides indicated by the tick marks on all 4 sides.

We will call side RQ = the hypotenuse
or side “c” = 30
We know RM is leg “b” = 24
Side “a” is our unknown QM

Our formula is
a^2 + b^2 = c^2

a^2 + 24^2 = 30^2

a^2 + 576 = 900

a^2 = 900 - 576

a^2 = 324

Take square root of both sides to solve a

a = 18

QM = 18

3 0
1 year ago
Ten years ago 53% of American families owned stocks or stock funds. Sample data collected by the Investment Company Institute in
Alborosie

Answer:

a) Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

b) z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

p_v =P(Z

c) So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

\hat p=0.46 estimated proportion of American families owning stocks or stock funds

p_o=0.53 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

Part a

We need to conduct a hypothesis in order to test the claim that proportion is less than 0.53 or 53%.:  

Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

Part b

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z

Part c  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

7 0
3 years ago
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