Question

6-√8 divide √2-1

Answer 1

Answer:

4$\sqrt{2}$  +2

Step-by-step explanation:

$\frac{6-\sqrt{8}}{\sqrt{2}-1}$

=$\frac{6-\sqrt{8}}{\sqrt{2}-1}$ ×$\frac{\sqrt{2}+1}{\sqrt{2}+1}$

=$\frac{(6-\sqrt{8})(\sqrt{2}+1)}{2-1}$

=6$\sqrt{2}$ + 6 -$\sqrt{8}\sqrt{2}$ - $\sqrt{8}$

=6$\sqrt{2}$ + 6 - 4 - $\sqrt{8}$

=6$\sqrt{2}$ + 2 - $\sqrt{8}$

=6$\sqrt{2}$ + 2 - 2

=4$\sqrt{2}$  +2

for $\sqrt{8}$ = 2$\sqrt{2}$ ,

$\sqrt{8}$ = $\sqrt{2*2*2}$

     = ($\sqrt{2}$)^2 × $\sqrt{2}$

     =2 ×$\sqrt{2}$