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soldi70 [24.7K]
3 years ago
15

6-√8 divide √2-1

Mathematics
1 answer:
agasfer [191]3 years ago
5 0

Answer:

4\sqrt{2}  +2

Step-by-step explanation:

\frac{6-\sqrt{8}}{\sqrt{2}-1}

=\frac{6-\sqrt{8}}{\sqrt{2}-1} ×\frac{\sqrt{2}+1}{\sqrt{2}+1}

=\frac{(6-\sqrt{8})(\sqrt{2}+1)}{2-1}

=6\sqrt{2} + 6 -\sqrt{8}\sqrt{2} - \sqrt{8}

=6\sqrt{2} + 6 - 4 - \sqrt{8}

=6\sqrt{2} + 2 - \sqrt{8}

=6\sqrt{2} + 2 - 2

=4\sqrt{2}  +2

for \sqrt{8} = 2\sqrt{2} ,

\sqrt{8} = \sqrt{2*2*2}

     = (\sqrt{2})^2 × \sqrt{2}

     =2 ×\sqrt{2}

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