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Juliette [100K]
3 years ago
6

Please help I´ll give brainlist !

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
7 0

Answer

(-5,0)

Step-by-step explanation:

vladimir1956 [14]3 years ago
5 0
(-5,0) hope this helps :)
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Tell whether the following equations are true or false. Then, explain your reasoning.
lorasvet [3.4K]

Answer and explanation:

Given : Equations

1) x + 6g-6g = x

2) 2f-4e + 4e = 2f

To find : Tell whether the following equations are true or false. Then, explain your reasoning.

Solution :

Equation means when left hand side and right hand side of the equation is same.

1) x + 6g-6g = x

Take LHS,

LHS=x + 6g-6g

Same term with opposite sign cancel each other or sum is zero,

LHS=x

LHS=RHS

Therefore, Yes, it is true as it satisfy definition of equation.

2) 2f-4e + 4e = 2f

Take LHS,

LHS=2f-4e + 4e

Same term with opposite sign cancel each other or sum is zero,

LHS=2f

LHS=RHS

Therefore, Yes, it is true as it satisfy definition of equation.

4 0
4 years ago
Please help asap, thanks!!
labwork [276]

Answer:

y=0

Step-by-step explanation:

m=y change in y/change in x

2+3/-2+2 = 5/0

6 0
3 years ago
a girl has a coloring book with 60 pages in it. she uses 5 pages every 3 days. How many days will it take her to finish the colo
Ad libitum [116K]
I believe the answer is 7
7 0
4 years ago
Read 2 more answers
Find the area enclosed by the curve<br> x = t2 − 2t, y = t and the y-axis.
MA_775_DIABLO [31]
The curve hits the y-axis whenever x=0:

x=t^2-2t=0\implies t(t-2)=0\implies t=0,t=2

The area enclosed by the region is the sum of distances of every point on the curve where t\in[0,2] to the origin. This is given by the integral

\displaystyle\int_0^2\sqrt{x(t)^2+y(t)^2}\,\mathrm dt
\displaystyle\int_0^2\sqrt{(t^2-2t)^2+t^2}\,\mathrm dt
\displaystyle\int_0^2\sqrt{t^2(t-2)^2}\,\mathrm dt
\displaystyle\int_0^2|t||t-2|\,\mathrm dt

Since t\in[0,2], you have |t|=t and |t-2|=-(t-2)=2-t, giving you

\displaystyle\int_0^2(2t-t^2)\,\mathrm dt=t^2-\dfrac{t^3}3\bigg|_{t=0}^{t=2}=4-\dfrac83=\dfrac43
7 0
3 years ago
Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1. (2 points)
Anastasy [175]
To determine the equation of the parabola with the given features above, we need to understand or know what are the significance of those values. The directrix is a line that is perpendicular to the axis of symmetry of a curve. A parabola is defined by its focus and the directrix. The parabola is a group of points where the distance to its focus is equal to the distance to its directrix. So, the directrix for this case is all points (x, -1). By using the distance formula, we construct the equation.

√((x-0)^2 + (y-1)^2) = √((x-x)^2 + (y+1)^2)
x^2 + (y-1)^2 = (y+1)^2
x^2 + y^2 - 2y+1 = y^2 +2y + 1
x^2 - 2y = 2y
x^2 = 4y
y = x^2/4
4 0
3 years ago
Read 2 more answers
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